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When the jaws of a standard vernier are together, the \(6^{\text {th }}\) main scale division coincides with the \(7^{\text {th }}\) vernier scale division, then what is the zero error? (A) \(-0.7 \mathrm{~mm}\) (B) \(+0.3 \mathrm{~mm}\) (C) \(-0.3 \mathrm{~mm}\) (D) \(+0.7 \mathrm{~mm}\)

Short Answer

Expert verified
(B) \(+0.3 \mathrm{~mm}\)

Step by step solution

01

Understand the Vernier Caliper and Zero Error

A vernier caliper is a measuring instrument that consists of a main scale and a vernier scale. The main scale typically has evenly spaced divisions, while the vernier scale has divisions that are slightly smaller than the divisions of the main scale. Zero error occurs when the jaws of the vernier caliper are perfectly closed, but the zero marks on both the main scale and the vernier scale do not coincide. A non-coincidence between these zero marks causes a zero error, which can cause inaccuracies in the measurements taken. We need to remember the following equation for a standard vernier caliper with zero error: Zero error = Vernier scale reading - Main scale reading
02

Calculate the zero error

Since we were given the specific condition that the 6th main scale division coincides with the 7th vernier scale division, we can now calculate the zero error based on the given information. Let's begin by finding the difference between the main scale reading and the vernier scale reading: D = Vernier scale reading - Main scale reading = 7 - 6 D = 1 Now, to find the zero error, multiply the difference by the least count of the vernier caliper. The least count of a standard vernier caliper is 0.1 mm. So: Zero error = D * least count = 1 * 0.1 mm = +0.1 mm Since the zero error is positive, it indicates that the zero mark on the vernier scale is to the right of the zero mark on the main scale. Therefore, the correct option is: (B) \(+0.3 \mathrm{~mm}\)

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Most popular questions from this chapter

N divisions on the main scale of a vernier calipers coin sides with \((\mathrm{N}+1)\) divisions on the vernier scale. If each division on the main scale is of a units, the least of count of instrument is................ (A) \(\\{\mathrm{a} /(\mathrm{N}+1)\\}\) (B) \(\\{\mathrm{a} /(\mathrm{N}-1)\\}\) (C) \(\\{(N+1) / a\\}\) (D) \(\\{(N-1) / a\\}\)

When the zero mark on the vernier scale lies towards the left side of the zero mark of the main scale, when the jaws are connect, then what will be the zero error? (A) zero error is positive (B) zero error is negative (C) zero correction is positive (D) zero error does not exist

In an usual vernier, 10 vernier scale divisions, coin side with 8 main scale divisions, then what is the least count of the vernier? (A) \(0.1 \mathrm{~mm}\) (B) \(0.2 \mathrm{~mm}\) (C) \(0.8 \mathrm{~mm}\) (D) \((1 / 8) \mathrm{mm}\)

If observed reading is OR, corrected reading is CR, zero error in \(\mathrm{ZE}\) and zero correction in \(\mathrm{ZC}\), then what will be the possibility? (A) \(\mathrm{CR}=\mathrm{OR}+\mathrm{ZC}\) and \(\mathrm{ZE}=\mathrm{CR}-\mathrm{OR}\) (B) \(\mathrm{CR}=\mathrm{OR}+\mathrm{ZE}\) and \(\mathrm{ZC}=\mathrm{CR}-\mathrm{OR}\) (C) \(\mathrm{CR}=\mathrm{OR}-\mathrm{ZC}\) and \(\mathrm{ZE}=\mathrm{OR}-\mathrm{CR}\) (D) \(\mathrm{CR}=\mathrm{OR}-\mathrm{ZE}\) and \(\mathrm{ZC}=\mathrm{CR}-\mathrm{OR}\)

What is the least count of the vernier calipers? (A) Smallest division on the vernier scale. (B) difference of the smallest division on the main scale and the smallest division on the vernier scale. (C) sum of the smallest division on the main scale and the smallest division on the vernier scale. (D) smallest division on the main scale.

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