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In Bohr model the hydrogen atom, the lowest orbit corresponds to (A) Infinite energy (B) zero energy (C) The minimum energy (D) The maximum energy

Short Answer

Expert verified
(C) The minimum energy

Step by step solution

01

Determine the energy level of the ground state (n=1)

Using the Bohr model formula with n=1, we will find the energy level of the ground state. \(E_1 = -\dfrac{13.6 eV}{1^2} = -13.6 eV\)
02

Evaluate the given options

Now, we will examine the provided options to see which one corresponds to the energy level of the ground state: (A) Infinite energy: The energy level we calculated is not infinite. Thus, this option is incorrect. (B) Zero energy: The energy level for the ground state is not zero. Therefore, this option is incorrect as well. (C) The minimum energy: The ground state is the lowest energy level that the atom can occupy, and the energy level is negative. As the atom goes to the higher energy levels (higher orbits), the energy increases and approaches zero, but never exceeds zero. Thus, the ground state corresponds to the minimum energy; this option is correct. (D) The maximum energy: Since the energy levels increase with higher orbits, the ground state cannot be the maximum energy level. So, this option is incorrect. Based on our evaluation, the correct answer is: (C) The minimum energy

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Most popular questions from this chapter

According to Bohr's theory the radius of electron in an orbit described by Principal quantum number \(\mathrm{n}\) and atomic number \(Z\), is Proportional to. (A) \(Z^{2} n^{2}\) (B) \(\left(\mathrm{n}^{2} / \mathrm{Z}\right)\) (C) \(\left(\mathrm{Z}^{2} / \mathrm{n}\right)\) (D) \(\left(\mathrm{n} / \mathrm{Z}^{2}\right)\)

which of the following isotopes normally fissionable (A) \({ }_{92} \mathrm{U}^{233}\) (B) \({ }_{92} \mathrm{U}^{238}\) (C) \({ }_{92} \mathrm{U}^{235}\) (D) \({ }_{93} \mathrm{~Np}^{239}\)

Match column I and II and chose correct Answer form the given below. (a) Nuclear fusion (p) converts some matter into energy (b) Nuclear fission (q) generally Possible for nuclei with low atomic number (c) \(\beta\) decay (r) generally Possible for nuclei with high atomic number (d) Exothermic nuclear (s) Essentially Proceeds by weak reaction nuclear force(c) (A) $\mathrm{a} \rightarrow \mathrm{p}, \mathrm{b} \rightarrow \mathrm{r}, \mathrm{c} \rightarrow \mathrm{s}, \mathrm{d} \rightarrow \mathrm{q}$ (B) $\mathrm{a} \rightarrow \mathrm{q}, \mathrm{b} \rightarrow \mathrm{r}, \mathrm{c} \rightarrow \mathrm{p}, \mathrm{d} \rightarrow \mathrm{s}$ (C) $\mathrm{a} \rightarrow \mathrm{q}, \mathrm{b} \rightarrow \mathrm{r}, \mathrm{c} \rightarrow \mathrm{s}, \mathrm{d} \rightarrow \mathrm{p}$ (D) $\mathrm{a} \rightarrow \mathrm{r}, \mathrm{b} \rightarrow \mathrm{q}, \mathrm{c} \rightarrow \mathrm{p}, \mathrm{d} \rightarrow \mathrm{s}$

If \(\mathrm{M}_{0}\) is the mass of an isotope, ${ }^{17}{ }_{8} \mathrm{O}, \mathrm{M}_{\mathrm{p}}\( and \)\mathrm{M}_{\mathrm{n}}$ are the masses of a Proton and neutron respectively, the binding energy of the isotope is (A) \(\left(\mathrm{M}_{0}-8 \mathrm{M}_{\mathrm{p}}\right) \mathrm{C}^{2}\) (B) $\left(\mathrm{M}_{0}-8 \mathrm{M}_{p}-9 \mathrm{M}_{\mathrm{n}}\right) \mathrm{C}^{2}$ (C) \(\left(\mathrm{M}_{0}-17 \mathrm{M}_{\mathrm{n}}\right) \mathrm{C}^{2}\) (D) \(\mathrm{M}_{\mathrm{O}} \mathrm{C}^{2}\)

In which region of electromagnetic spectrum does the Lyman series of hydrogen atom like (A) \(x\) -ray (B) Infrared (C) visible (D) ultraviolet

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