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Match column I and II and chose correct Answer form the given below. (a) Nuclear fusion (p) converts some matter into energy (b) Nuclear fission (q) generally Possible for nuclei with low atomic number (c) \(\beta\) decay (r) generally Possible for nuclei with high atomic number (d) Exothermic nuclear (s) Essentially Proceeds by weak reaction nuclear force(c) (A) $\mathrm{a} \rightarrow \mathrm{p}, \mathrm{b} \rightarrow \mathrm{r}, \mathrm{c} \rightarrow \mathrm{s}, \mathrm{d} \rightarrow \mathrm{q}$ (B) $\mathrm{a} \rightarrow \mathrm{q}, \mathrm{b} \rightarrow \mathrm{r}, \mathrm{c} \rightarrow \mathrm{p}, \mathrm{d} \rightarrow \mathrm{s}$ (C) $\mathrm{a} \rightarrow \mathrm{q}, \mathrm{b} \rightarrow \mathrm{r}, \mathrm{c} \rightarrow \mathrm{s}, \mathrm{d} \rightarrow \mathrm{p}$ (D) $\mathrm{a} \rightarrow \mathrm{r}, \mathrm{b} \rightarrow \mathrm{q}, \mathrm{c} \rightarrow \mathrm{p}, \mathrm{d} \rightarrow \mathrm{s}$

Short Answer

Expert verified
The short answer is: (C) a → q, b → r, c → s, d → p

Step by step solution

01

(Step 1: Matching Nuclear Fusion)

Nuclear fusion typically involves nuclei with low atomic numbers, and it converts some matter into energy. So, we can match (a) to (p) and (q).
02

(Step 2: Matching Nuclear Fission)

Nuclear fission generally occurs with nuclei with high atomic numbers, and it results in the release of energy. So, we can match (b) to (r).
03

(Step 3: Matching \(\beta\) Decay)

\(\beta\) decay is a type of radioactive decay that involves the weak nuclear force. So, we can match (c) to (s).
04

(Step 4: Matching Exothermic Nuclear)

Exothermic nuclear reactions are those that result in the production of energy, typically through releasing heat. This aligns with the concept of converting some matter into energy. So, we can match (d) to (p). After matching each term with their corresponding phrase in column II, we obtain the following result: a → q, b → r, c → s, d → p By comparing this with the given choices, we identify the correct answer as: (C) a → q, b → r, c → s, d → p

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