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Chapter 16: Problem 2231

In which of the following cases a man will not see image greater than himself. (A) convex mirror (B) concave mirror (C) plane mirror (D) none of these

Short Answer

Expert verified
In a convex mirror (Option A), a man will not see an image greater than himself, as the images formed are always virtual, upright, and smaller than the object.

Step by step solution

01

Understanding convex mirrors

A convex mirror is a curved mirror with the reflecting surface bulging outward. Images formed in convex mirrors are always virtual, upright, and smaller than the object.
02

Understanding concave mirrors

A concave mirror is a curved mirror with the reflecting surface curving inward. Images formed in concave mirrors can be real or virtual, and their size (magnified or diminished) depends on the object's location relative to the mirror's focal point.
03

Understanding plane mirrors

A plane mirror is a flat mirror, and the images formed are always virtual, upright, and the same size as the object.
04

Comparing image sizes in different mirrors

By analyzing the properties of each type of mirror, we can deduce the following: - Convex mirror: The image is always smaller than the object. - Concave mirror: The image size depends on the object's location. It can be larger, smaller, or equal to the object size. - Plane mirror: The image size is always equal to the object size.
05

Identifying the correct answer

From our analysis, we can conclude that in the case of a convex mirror (Option A), a man will not see an image greater than himself. The image will always be smaller and upright.

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Most popular questions from this chapter

The power of plane glass is (A) \(\infty\) (B) 0 (C) \(\overline{2 \mathrm{D}}\) (D) \(4 \mathrm{D}\)

If thin prism of \(5^{\circ}\) gives a deviation of \(2^{\circ}\) then the refractive index of material of prism is (A) \(1.4\) (B) \(1.5\) (C) \(1.6\) (D) \(1.0\)

In young's double slit experiment if the width of \(3^{\text {rd }}\) fringe is \(10^{-2} \mathrm{~cm}\), then the width of \(5^{\text {th }}\) fringe will be \(\mathrm{cm} .\) (A) \(10^{-2}\) (B) \(5 \times 10^{-2}\) (C) \(2 \times 10^{-2}\) (D) \(10^{+2}\)

$$ \begin{array}{|l|l|} \hline \text { Column - I } & \text { Column - II } \\ \hline \text { (i) Minimum deviation } & \text { (a) }(\mathrm{n}-1) \mathrm{A}+\left(\mathrm{n}^{\prime}-1\right) \mathrm{A}^{\prime}=0 \\ \text { (ii) Angular dispersion } & \text { (b) }\left[\left(\mathrm{n}_{\mathrm{v}}-\mathrm{n}_{\mathrm{r}}\right) /(\mathrm{n}-1)\right] \\ \text { (iii) Dispersive power } & \text { (c) }\left(\mathrm{n}_{\mathrm{v}}-\mathrm{n}_{\mathrm{r}}\right) \mathrm{A} \\ \text { (iv) Condition for no deviation } & \text { (d) }(\mathrm{n}-1) \mathrm{A} \\ \hline \end{array} $$ (A) \(i-c\), ii \(-d\), ii \(-b\), iv-a (B) \(i-a, 1 i-b\), iii \(-c\), iv-d (C) \(i-c\), ii \(-b\), ii \(-a\), iv-d (D) $\mathrm{i}-\mathrm{d}, \mathrm{i} i-\mathrm{c}, \mathrm{ii}-\mathrm{b}, \mathrm{iv}-\mathrm{a}$

A concave mirror of focal length \(20 \mathrm{~cm}\) forms an virtual image having twice the linear dimensions of the object, the position of the object will be \(\mathrm{cm}\) (A) \(7.5\) (B) \(-10\) (C) 10 (D) \(-7.5\)
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