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A Plane mirror produces a magnification of (A) 0 (B) \(+1\) (C) \(-1\) (D) \(\infty\)

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(B) \(+1\)

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01

Answer

(B) \(+1\)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Magnification
Magnification is a key concept in optics that describes how much larger or smaller an image appears compared to the actual object. In the case of plane mirrors, the magnification is always +1. This means the image produced is the same size as the object. The formula to express magnification is given by:
\[ m = \frac{h_i}{h_o} \]
where \( h_i \) is the height of the image and \( h_o \) is the height of the object. For plane mirrors:
  • The object distance is equal to the image distance.
  • The height of the image equals the height of the object (\( h_i = h_o \)).
So, when looking into a plane mirror, you will see a life-sized reflection of yourself or any object placed in front of it.This consistency makes plane mirrors useful in everyday applications like grooming mirrors, interior decorations, and periscopes.
Reflection
Reflection is the phenomenon where light bounces off a surface. In the context of plane mirrors, reflection obeys the laws of reflection. These are:
  • The angle of incidence is equal to the angle of reflection.
  • The incident ray, the reflected ray, and the normal to the surface all lie in the same plane.
A plane mirror reflects light in a predictable pattern, which is why the image appears upright and is the same size as the object. Because the light path is reversible, if you change your position relative to the mirror, the image appears to move, maintaining the same lateral positioning.Transformations: - The image is laterally inverted, swapping left and right sides. - However, vertical orientation remains unchanged. Examples of this can be observed when writing on paper and observing how letters appear reversed in the mirror.
Optics
Optics is the branch of physics that studies light and its interactions. Plane mirrors are a fundamental topic within optics. They demonstrate basic principles of image formation, which are also applicable to more complex optical devices:
  • A plane mirror forms virtual images, meaning the image cannot be projected on a screen.
  • Understanding plane mirrors helps us grasp concepts of real and virtual images seen in curved mirrors or lenses.
Applications of plane mirrors in optics include periscopes and kaleidoscopes, which use multiple reflections to achieve desired effects. The simple yet precise laws governing plane mirrors provide foundational knowledge that is built upon in complex optical systems such as cameras, telescopes, and microscopes. Optics reveals how plane mirrors integrate into daily practical tools and scientific instruments alike. This integration emphasizes the importance of mastering basic optical principles to explore advanced technological applications.

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Most popular questions from this chapter

The distance between the first and sixth minima in the diffraction pattern of a single slit, it is \(0.5 \mathrm{~mm}\). The screen is \(0.5 \mathrm{~m}\) away from the Slit. If the wavelength of light is \(5000 \AA\), then the width of the slit will be \(\mathrm{mm}\) (D) \(1.0\) (A) 5 (B) \(2.5\) (C) \(1.25\)

A concave lens forms the image of an object such that the distance between the object and the image is \(10 \mathrm{~cm}\) and the magnification produced is \((1 / 4)\), the focal length of lens will be \(\mathrm{cm}\) (A) - 6.2 (B) \(-12.4\) (C) \(-4.4\) (D) \(-8.8\)

It is difficult to see through the fog because (A) light is scattered by the droplets in the fog. (B) fog absorbs light. (C) refractive index of fog is infinity. (D) light suffers total internal refection.

The power of plane glass is (A) \(\infty\) (B) 0 (C) \(\overline{2 \mathrm{D}}\) (D) \(4 \mathrm{D}\)

Read the paragraph and chose the correct answer of the following questions In young experiment position of bright fringes is given by \(\mathrm{x}=\mathrm{n} \lambda(\mathrm{D} / \mathrm{d})\) and the position of dark fringes is given by \(\mathrm{x}=(2 \mathrm{n}-1)(N 2)(\mathrm{D} / \mathrm{d})\) where \(\mathrm{n}=1,2,3 \ldots \ldots \ldots \ldots\) for first second, third bright/dark fringe. The center of the fringe pattern is bright (for \(\mathrm{n}=0\) ). The width of each bright/dark fringe is \(\beta=(\lambda \mathrm{D} / \mathrm{d})\), Where \(\lambda=5000 \AA\). Slits are \(0.2 \mathrm{~cm}\) apart and \(\mathrm{D}=1 \mathrm{~m}\) (i) If light of wavelength \(6000 \AA\) be used in the above experiment the fringe width would be \(\mathrm{mm}\) (A) \(0.30\) (B) 3 (C) \(0.6\) (D) 6 (ii) with the light of wavelength \(5000 \AA\), If experiment were carried out under water of a \(n=(4 / 3)\) the fringe width would be (A) zero (B) \((4 / 3)\) times (C) (3/4) times (D) none of these

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