Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

"Bhautik" runs towards a plane mirror with a speed of \(20 \mathrm{~ms}^{-1}\), what is the speed of his image ? (A) \(45 \mathrm{~ms}^{-1}\) (B) \(20 \mathrm{~ms}^{-1}\) (C) \(15 \mathrm{~ms}^{-1}\) (D) \(7.5 \mathrm{~ms}^{-1}\)

Short Answer

Expert verified
The speed of Bhautik's image in the plane mirror is \(20 \mathrm{~ms}^{-1}\). Therefore, the correct answer is (B) \(20 \mathrm{~ms}^{-1}\).

Step by step solution

01

Analyze the movement with respect to the mirror

When Bhautik is running towards the mirror, the distance between him and the mirror is decreasing at a rate of \(20 \mathrm{~ms}^{-1}\). As the plane mirror forms an image that has the same distance away from it as the object, the image will also move in the same direction as Bhautik.
02

Find the speed of the image in the mirror

Since we know that the distance between the object (Bhautik) and its image in the plane mirror are equal and they are moving towards each other in the same direction, the speed of the image will also be equal to the speed of Bhautik.
03

Write the final answer

The speed of Bhautik's image in the plane mirror is \(20 \mathrm{~ms}^{-1}\). Therefore, the correct answer is (B) \(20 \mathrm{~ms}^{-1}\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

The width of a single slit, if the first minimum is observed at an angle of \(2^{\circ}\) with a wavelength of light \(6980 \AA\) is \(\mathrm{mm}\) (A) \(0.2\) (B) \(2 \times 10^{-5}\) (C) \(2 \times 10^{5}\) (D) \(0.02\)

For four different transparent medium $\mathrm{n}_{41} \times \mathrm{n}_{12} \times \mathrm{n}_{21}=$ (A) \(\left(1 / \mathrm{n}_{41}\right)\) (B) \(\mathrm{n}_{41}\) (C) \(\mathrm{n}_{14}\) (D) \(\left(1 / \mathrm{n}_{14}\right)\)

A double convex lens of focal length \(6 \mathrm{~cm}\) is made of glass of refractive index \(1.5\), The radius of curvature of one surface is double than that of the other surface. The value of small radius of curvature is (A) 6 (B) 9 (C) 12 (D) \(4.5\)

A prism of certain angle deviates the red and blue rays by \(8^{\circ}\) and \(12^{\circ}\) respectively. Another prism of the same prism angle deviates the red and blue ray by \(10^{\circ}\) and \(14^{\circ}\) respectively. The prism are small angle and made of different materials. The dispersive powers of the materials of the prisms are in the ratio (A) \(5: 6\) (B) \(9: 11\) (C) \(6: 5\) (D) \(11: 9\)

$$ \begin{array}{|l|l|} \hline \text { Column - I } & \text { Column - II } \\ \hline \text { (i) While going from rarer to denser medium } & \text { (a) Wavelength changes } \\ \text { (ii) While going from denser to rarer medium } & \text { (b) } \eta=(\mathrm{C} / \mathrm{V}) \\ \text { (iii) While going to one medium to another } & \text { (C) Ray bends towards normal } \\ \text { (iv) Refractive index of medium } & \text { (D) Rav bends awav from normal } \\ \hline \end{array} $$ (A) \(i-c\), ii \(-d\), iii \(-b\), iv-a (B) \(\mathrm{i}-\mathrm{a}\), ii \(-\mathrm{b}\), iii $-\mathrm{c}, \mathrm{iv}-\mathrm{d}$ (C) $\mathrm{i}-\mathrm{c}, \mathrm{ii}-\mathrm{b}, \mathrm{iii}-\mathrm{a}, \mathrm{iv}-\mathrm{d}$ (D) \(i-d, 1 i-c, 11 i-b, i v-a\)

See all solutions

Recommended explanations on English Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free