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The core of a transformer is laminated so that...... (a) Ratio of I/ \(p\) \& O/p voltage increases (b) Rusting of core may be stopped (c) Energy loss due to eddy current may be reduced (d) Change in flux is increased

Short Answer

Expert verified
The core of a transformer is laminated to minimize eddy currents and reduce energy loss. By breaking the core into thin, insulated layers, it restricts the flow of eddy currents, significantly reducing energy loss due to heating. The correct reason for having a laminated core is: (c) Energy loss due to eddy current may be reduced.

Step by step solution

01

Understanding transformers

A transformer is an electrical device used to transfer electrical energy between two or more circuits through electromagnetic induction. It consists of coils called primary and secondary windings, wound around a core, which is usually made of iron.
02

Exploring the core's role in transformers

The core of a transformer acts as a path for magnetic flux. By forming a closed loop, it directs the magnetic flux created by the primary winding to the secondary winding, allowing energy to be transferred between the two coils.
03

Discussing eddy currents and energy loss

Eddy currents are generated in the transformer core due to the changing magnetic field. These currents flow inside the core material, producing heat and leading to energy loss. An ideal core should have minimum energy loss to ensure maximum efficiency of the transformer.
04

Examining the reason for a laminated core

The core of a transformer is laminated to minimize eddy currents and the resulting energy loss. By breaking the core into thin, insulated layers, it restricts the flow of eddy currents, significantly reducing energy loss due to heating.
05

Identifying the correct reason from the options

Based on the explanation given in the previous steps, it is clear that the purpose of laminating the core of a transformer is to reduce energy loss due to eddy currents. Therefore, the correct option is: (c) Energy loss due to eddy current may be reduced

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Eddy Currents
Eddy currents are swirling currents that occur inside conductors. They are caused by a changing magnetic field. This phenomenon is named 'eddy currents' because these currents can look like swirling whirlpools. In a transformer, the core material experiences these changing magnetic fields constantly.

When the magnetic field in the core varies, it induces these unwanted currents in the metal. These eddy currents flow in circular paths within the conductor, generating heat. This heat is actually energy which was ideally supposed to be transferred efficiently across the transformer's coils.

High eddy current losses can cause:
  • Overheating of the transformer core
  • Decreased efficiency
  • Wasted energy
By understanding how eddy currents operate, engineers strive to innovate ways to minimize these currents and, in turn, minimize energy loss.
Laminated Core
A laminated core is used in transformers to combat the problem of eddy currents. The core is made of many thin sheets, or "laminations," that are electrically insulated from each other.

This design effectively breaks the path of eddy currents. Rather than a continuous block of metal where currents could flow freely, the laminated core restricts these paths. It works by reducing the area where these currents can flow.

Some key benefits of using a laminated core include:
  • Reduced eddy current paths
  • Lower heat generation
  • Increased efficiency of the transformer
By using a laminated structure, transformers can perform more reliably and efficiently, sustaining a longer life with less energy wasted.
Energy Loss Reduction
In a transformer's operation, energy loss is a significant concern. When energy is not efficiently transferred, it can result in wasted resources, higher operational costs, and potential damage to the equipment.

The reduction of energy loss is primarily achieved through:
  • Using laminated cores, which, as discussed, minimize eddy currents
  • Materials with high magnetic permeability that guide magnetic flux effectively
  • Proper design and engineering of the winding materials
A reduced energy loss in a transformer not only boosts efficiency but also enhances the overall performance of the electrical system it serves.

The ultimate goal is to have transformers that use less energy to function, ensuring they deliver maximum power transfer with minimal losses. This ensures a more sustainable and cost-effective solution for energy distribution.

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Most popular questions from this chapter

An LC circuit contains a \(20 \mathrm{mH}\) inductor and a \(50 \mu \mathrm{F}\) capacitor with an initial charge of \(10 \mathrm{mc}\). The resistance of the circuit is negligible. At the instant the circuit is closed be \(t=0 .\) At what time is the energy stored completely magnetic. (a) \(\mathrm{t}=0 \mathrm{~ms}\) (b) \(\mathrm{t}=1.54 \mathrm{~ms}\) (c) \(\mathrm{t}=3.14 \mathrm{~ms}\) (d) \(\mathrm{t}=6.28 \mathrm{~ms}\)

Two identical circular loops of metal wire are lying on a table near to each other without touching. Loop A carries a current which increasing with time. In response the loop B......... (a) Is repelled by loop \(\mathrm{A}\) (b) Is attracted by loop \(\mathrm{A}\) (c) rotates about its centre of mass (d) remains stationary

A conducting rod \(P Q\) of length \(4 \ell\) is rotated about a point \(O\) in a uniform magnetic field \(\mathrm{B} \rightarrow \mathrm{PO}=\ell\) Then (a) \(\mathrm{V}_{\mathrm{Q}}-\mathrm{V}_{\mathrm{P}}=-\left[\left\\{\mathrm{B} \omega \ell^{2}\right\\} /\right.\) \(\\{2\\}] \quad\) (b) \(\mathrm{V}_{\mathrm{Q}}-\mathrm{V}_{\mathrm{O}}=(5 / 2) \mathrm{B} \operatorname{co} \ell^{2}\) (c) \(\mathrm{V}_{Q}-\mathrm{V}_{\mathrm{O}}=(9 / 2) \mathrm{B} \omega \ell^{2}\) (d) \(\mathrm{V}_{\mathrm{P}}-\mathrm{V}_{\mathrm{Q}}=4 \mathrm{~B} \omega \ell^{2}\)

In general in an alternating current circuit. (a) The average value of current is zero. (b) The average value of square of current is zero. (c) Average power dissipation is zero. (d) The phase difference between voltage and current is zero.

When 100 volt dc is applied across a coil, a current of \(1 \mathrm{~A}\) flows through it. When 100 volt ac at 50 cycle \(\mathrm{s}^{-1}\) is applied to the same coil, only \(0.5\) A current flows. The impedance of the coil is, (a) \(100 \Omega\) (b) \(200 \Omega\) (c) \(300 \Omega\) (d) \(400 \Omega\)

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