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The direction of mag. field lines close to a straight conductor carrying current will be (a) Along the length of the conductor (b) Radially outward (c) Circular in a plane perpendicular to the conductor (d) Helical

Short Answer

Expert verified
The direction of the magnetic field lines close to a straight conductor carrying current is (c) Circular in a plane perpendicular to the conductor, as determined by the right-hand rule for a straight conductor.

Step by step solution

01

Right-Hand Rule for a Straight Conductor

To find the direction of the magnetic field around a straight conductor carrying current, use the right-hand rule. To apply the rule, put your right thumb in the direction of the current and curl your fingers around the wire. The direction in which your fingers curl is the direction of the magnetic field.
02

Analyze the Given Options

Now, we consider each of the given options and see if they match the result from the right-hand rule. (a) Along the length of the conductor: The right-hand rule indicates that the magnetic field direction is circular around the wire, not along its length. (b) Radially outward: The magnetic field direction from the right-hand rule is circular and not radially outward. (c) Circular in a plane perpendicular to the conductor: This option matches the result obtained from the right-hand rule, where the magnetic field direction is circular around the wire, and the plane of the circles is perpendicular to the conductor. (d) Helical: The magnetic field direction we found using the right-hand rule is not helical.
03

Choose the Correct Option

Based on the analysis of the given options, we conclude that the direction of the magnetic field lines close to a straight conductor carrying current is (c) Circular in a plane perpendicular to the conductor.

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Most popular questions from this chapter

A straight wire of length \(30 \mathrm{~cm}\) and mass 60 milligram lies in a direction \(30^{\circ}\) east of north. The earth's magnetic field at this site is horizontal and has a magnitude of \(0.8 \mathrm{G}\). What current must be passed through the wire so that it may float in air ? \(\left[\mathrm{g}=10\left(\mathrm{~m} / \mathrm{s}^{2}\right)\right]\) (a) \(10 \mathrm{Amp}\) (b) \(20 \mathrm{Amp}\) (c) \(40 \mathrm{Amp}\) (d) \(50 \mathrm{Amp}\)

The strength of the magnetic field at a point \(\mathrm{y}\) near a long straight current carrying wire is \(\mathrm{B}\). The field at a distance \(\mathrm{y} / 2\) will be (a) B/2 (b) B \(/ 4\) (c) \(2 \mathrm{~B}\) (d) \(4 \mathrm{~B}\)

An iron rod of length \(L\) and magnetic moment \(\mathrm{M}\) is bent in the form of a semicircle. Now its magnetic moment will be (a) \(\mathrm{M}\) (b) \((2 \mathrm{M} / \pi)\) (c) \((\mathrm{M} / \pi)\) (d) \(\mathrm{M} \pi\)

In each of the following questions, Match column-I and column-II and select the correct match out of the four given choices.\begin{tabular}{l|r} Column-I & Column - II \end{tabular} (A) Magnetic field induction due to Current 1 through straight conductor at a perpendicular distance \(\mathrm{r}\). (B) Magnetic field induction at (Q) \(\left[\left(\mu_{0} \mathrm{I}\right) /(4 \pi \mathrm{r})\right]\) the centre of current \((1)\) carrying Loop of radius (r) (C) Magnetic field induction at the (R) \(\left[\mu_{0} /(4 \pi)\right](2 \mathrm{I} / \mathrm{r})\) axis of current (1) carrying coil of radius (r) at a distance (r) from centre of coil (D) Magnetic field induction at the (S) \(\left[\mu_{0} /(4 \sqrt{2})\right](\mathrm{L} / \mathrm{r})\) at the centre due to circular arc of length \(\mathrm{r}\) and radius (r) carrying current (I) (a) $\mathrm{A} \rightarrow \mathrm{R} ; \mathrm{B} \rightarrow \mathrm{S} ; \mathrm{C} \rightarrow \mathrm{P} ; \mathrm{D} \rightarrow \mathrm{Q}$ (b) $\mathrm{A} \rightarrow \mathrm{R} ; \mathrm{B} \rightarrow \mathrm{P} ; \mathrm{C} \rightarrow \mathrm{S} ; \mathrm{D} \rightarrow \mathrm{Q}$ (c) $\mathrm{A} \rightarrow \mathrm{P} ; \mathrm{B} \rightarrow \mathrm{Q} ; \mathrm{C} \rightarrow \mathrm{S} ; \mathrm{D} \rightarrow \mathrm{R}$ (d) $\mathrm{A} \rightarrow \mathrm{Q} ; \mathrm{B} \rightarrow \mathrm{P} ; \mathrm{C} \rightarrow \mathrm{R} ; \mathrm{D} \rightarrow \mathrm{S}$

The true value of angle of dip at a place is \(60^{\circ}\), the apparent dip in a plane inclined at an angle of \(30^{\circ}\) with magnetic meridian is. (a) \(\tan ^{-1}(1 / 2)\) (b) \(\tan ^{-1} 2\) (c) \(\tan ^{-1}(2 / 3)\) (d) None of these

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