Chapter 10: Problem 1513
Standing waves are produced by the superposition of two waves \(\mathrm{y}_{1}=0.05 \sin (3 \pi \mathrm{t}-2 \mathrm{x})\) and \(\mathrm{y}_{2}=0.05 \sin (3 \pi \mathrm{t}+2 \mathrm{x})\) where \(\mathrm{x}\) and \(\mathrm{y}\) are in meters and \(\mathrm{t}\) is in seconds. The amplitude of a particle at \(\mathrm{x}=0.5 \mathrm{~m}\) is \(\ldots \ldots\) (A) \(1.08 \times 10^{-1} \mathrm{~m}\) (B) \(5.4 \times 10^{-2} \mathrm{~m}\) (C) \((\pi / 2) \times 10^{-1} \mathrm{~m}\) (D) \(\pi \times 10^{-1} \mathrm{~m}\)
Short Answer
Step by step solution
Key Concepts
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