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When temperature increases, the frequency of a tuning fork (A) Increases (B) Decreases (C) remains same (D) Increases or decreases depending on the material.

Short Answer

Expert verified
The correct answer is (D) Increases or decreases depending on the material, as the frequency change depends on the specific properties of the tuning fork's material.

Step by step solution

01

Recall the relationship between frequency and temperature

When the temperature of a tuning fork changes, its physical properties, such as its dimensions and materials, will also be affected. These changes can cause the frequency of the tuning fork to alter. However, the nature of this alteration (increase, decrease, or remain the same) depends on the material and the specific temperature range.
02

Analyze the options provided

Let's go through each provided option: (A) Increases: This suggests that as the temperature increases, the frequency of the tuning fork will always increase. (B) Decreases: This suggests that as the temperature increases, the frequency of the tuning fork will always decrease. (C) remains the same: This suggests that the frequency is not affected by the changes in temperature. (D) Increases or decreases depending on the material: This option leaves open the possibility that the temperature could have different effects on the frequency depending on the specific material of the tuning fork.
03

Determine the correct answer

We know that temperature can affect the physical properties of the tuning fork, which can lead to changes in its frequency. However, the specific relationship between temperature and frequency changes depends on the material. Thus, the correct answer is (D) Increases or decreases depending on the material.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Tuning Fork Material
The material of a tuning fork plays a critical role in how it interacts with changes in temperature. Different materials respond differently to heat, which in turn affects how the sound frequency changes. For example, metals like steel and aluminum, commonly used for tuning forks, have distinct thermal expansion coefficients. These coefficients determine how much a material will expand when heated. Some materials might expand more, leading to a decrease in frequency, while others expand less, which can cause an increase. This variability means that the material's properties must always be considered when predicting how temperature influences frequency.
Change in Dimensions
As temperature changes, so do the dimensions of a tuning fork. This is because most substances expand or contract with temperature variations. When a tuning fork expands, its vibrating length increases. This alteration affects the natural vibration frequency of the fork. Typically, an increase in length results in a lower frequency because longer objects vibrate more slowly. Conversely, if the temperature decrease causes the material to contract, the fork might vibrate faster, leading to a higher frequency. Thus, the frequency of sound produced by a tuning fork is directly linked to any changes in its dimensions caused by temperature shifts.
  • Expansion of tuning fork: Causes frequency to decrease.
  • Contraction of tuning fork: Can cause frequency to increase.
Temperature and Sound
Temperature is a key player in sound frequency modulation, particularly in tuning forks. Sound is essentially a wave, and its frequency determines its pitch. When a tuning fork's temperature changes, the sound waves it produces are also affected. If the temperature causes materials to expand, the frequency of sound produced generally decreases—resulting in a lower pitch.
However, this is not a strict rule, since the material's properties can drastically change the outcome. The important thing to remember is that the material and its reaction to temperature affect the sound frequency directly, showcasing the delicate interplay between temperature, material properties, and sound production.
Physical Properties
The physical properties of a tuning fork, such as its elasticity and density, have a profound impact on how temperature influences its sound frequency. When the temperature changes, it can affect the fork's stiffness and expansion rate, altering its physical dimensions.
Higher temperatures tend to increase the kinetic energy of particles, causing alterations in material density and elasticity. For example, softer materials might become more elastic and vibrate at higher frequencies when heated. Meanwhile, denser materials might react differently, leading to a divergent outcome. Understanding these nuances highlights why different materials produce varying sound frequency responses to temperature changes. Paying attention to these properties helps predict and explain the behavior of tuning forks under different thermal conditions.

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Most popular questions from this chapter

A block having mass \(\mathrm{M}\) is placed on a horizontal frictionless surface. This mass is attached to one end of a spring having force constant \(\mathrm{k}\). The other end of the spring is attached to a rigid wall. This system consisting of spring and mass \(\mathrm{M}\) is executing SHM with amplitude \(\mathrm{A}\) and frequency \(\mathrm{f}\). When the block is passing through the mid-point of its path of motion, a body of mass \(\mathrm{m}\) is placed on top of it, as a result of which its amplitude and frequency changes to \(\mathrm{A}^{\prime}\) and \(\mathrm{f}\). The ratio of amplitudes \(\left(\mathrm{A}^{1} / \mathrm{A}\right)=\ldots \ldots \ldots\) (A) \(\sqrt{\\{}(\mathrm{M}+\mathrm{m}) / \mathrm{m}\\}\) (B) \(\sqrt{\\{m} /(\mathrm{M}+\mathrm{m})\\}\) (C) \(\sqrt{\\{} \mathrm{M} /(\mathrm{M}+\mathrm{m})\\}\) (D) \(\sqrt{\\{}(\mathrm{M}+\mathrm{m}) / \mathrm{M}\\}\)

The distance travelled by a particle performing S.H.M. during time interval equal to its periodic time is \(\ldots \ldots\) (A) A (B) \(2 \mathrm{~A}\) (C) \(4 \mathrm{~A}\) (D) Zero.

As shown in figure, a spring attached to the ground vertically has a horizontal massless plate with a \(2 \mathrm{~kg}\) mass in it. When the spring (massless) is pressed slightly and released, the \(2 \mathrm{~kg}\) mass, starts executing S.H.M. The force constant of the spring is \(200 \mathrm{Nm}^{-1}\). For what minimum value of amplitude, will the mass loose contact with the plate? (Take \(\left.\mathrm{g}=10 \mathrm{~ms}^{-2}\right)\) (A) \(10.0 \mathrm{~cm}\) (B) \(8.0 \mathrm{~cm}\) (C) \(4.0 \mathrm{~cm}\) (D) For any value less than \(12.0 \mathrm{~cm}\).

The periodic time of two oscillators are \(\mathrm{T}\) and \((5 \mathrm{~T} / 4)\) respectively. Both oscillators starts their oscillation simultaneously from the midpoint of their path of motion. When the oscillator having periodic time \(\mathrm{T}\) completes one oscillation, the phase difference between the two oscillators will be \(\ldots \ldots \ldots\) (A) \(90^{\circ}\) (B) \(112^{\circ}\) (C) \(72^{\circ}\) (D) \(45^{\circ}\)

A rectangular block having mass \(\mathrm{m}\) and cross sectional area A is floating in a liquid having density \(\rho\). If this block in its equilibrium position is given a small vertical displacement, its starts oscillating with periodic time \(\mathrm{T}\). Then in this case \(\ldots \ldots\) (A) \(\mathrm{T} \propto(1 / \sqrt{\mathrm{m}})\) (B) \(T \propto \sqrt{\rho}\) (C) \(\mathrm{T} \propto(1 / \sqrt{\mathrm{A}})\) (D) \(\mathrm{T} \propto(1 / \sqrt{\rho})\)

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