Chapter 4: Problem 282
If the system of equations \(x+a y=0, a z+y=0, a x+z=0\) has infinite number of solutions then \(\mathrm{a}=\) (a) 0 (b) 1 (c) \(-1\) (d) \(-2\)
Short Answer
Expert verified
The correct value of \(a\) for the system of equations to have infinite solutions is \(a=-1\).
Step by step solution
01
Represent the system of equations in matrix form
The given system of equations can be represented as:
\[
\left|
\begin{array}{c c c}
1 & a & 0 \\
0 & 1 & a \\
a & 0 & 1
\end{array}
\right|
\]
Next, we need to find the determinant of the matrix.
02
Compute the determinant of the matrix
To find the determinant of the matrix, we first select the first row to find the co-factors and then compute the determinant using cofactor expansion.
The determinant of the given matrix is:
\[
\begin{vmatrix}
1 & a & 0 \\
0 & 1 & a \\
a & 0 & 1
\end{vmatrix} = 1\begin{vmatrix}1 & a \\ 0 & 1\end{vmatrix} - a\begin{vmatrix}0 & a \\ a & 1\end{vmatrix}
\]
Simplifying, we get the determinant as:
\(Det = 1(1) - a(0 - a^2) = 1 + a^3\)
03
Determine the condition for infinite solutions
To have infinite solutions, the determinant of the matrix must be zero. Thus,
\(Det = 1 + a^3 = 0\)
Now, we will find the value of 'a' that satisfies this equation.
04
Test the given options for 'a'
Now, we will test the given options for 'a' to find which one satisfies the condition for infinite solutions.
(a) 0:
\(1 + (0)^3 = 1\) (This doesn't satisfy the condition for infinite solutions)
(b) 1:
\(1 + (1)^3 = 2\) (This doesn't satisfy the condition for infinite solutions)
(c) -1:
\(1 + (-1)^3 = 0\) (This satisfies the condition for infinite solutions)
(d) -2:
\(1 + (-2)^3 = -7\) (This doesn't satisfy the condition for infinite solutions)
Since option (c) satisfies the condition for infinite solutions, the correct answer is:
\[\boxed{a = -1}\]
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with Vaia!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
System of Equations
A system of equations refers to a collection of two or more equations with a common set of variables. Solving such systems means finding the values of the variables that satisfy all the equations at once. These equations can often be linear, meaning that each variable appears with a power of one.
- The system given is:
1. \(x + ay = 0\) 2. \(az + y = 0\) 3. \(ax + z = 0\)
Infinite Solutions
Infinite solutions occur in a system of equations when there are an unlimited number of values for the variables that satisfy all the equations. This is often a result of the equations being dependent on each other. For a linear system represented by matrices, this occurs when the determinant of the corresponding matrix is zero.
- A zero determinant suggests that the equations in the system are dependent.
- This means that one or more of the equations can be derived algebraically from others.
Cramer's Rule
Cramer's Rule is a mathematical theorem used to solve systems of linear equations with as many equations as unknowns, which can be represented by matrices. It is particularly applicable to systems where the determinant of the coefficient matrix is non-zero.
- The rule states that each variable in the system can be expressed as a ratio of determinants.
- Specifically, if \( \det(A) eq 0 \), then each variable can be found by dividing the determinant of a modified matrix (formed by replacing one column of the original coefficient matrix with the constant terms) by the determinant of the coefficient matrix.
Matrix Representation
Matrix representation is a compact and organized way of expressing systems of equations, making them easier to manipulate and solve using linear algebra techniques. For a system of linear equations:
\[ \begin{bmatrix} 1 & a & 0 \ 0 & 1 & a \ a & 0 & 1 \end{bmatrix} \] This matrix form allows us to apply various techniques like finding determinants or using methods such as Gaussian elimination more straightforwardly. Such representation also helps in identifying properties like the zero determinant, leading to insights about the system's solutions.
- Each equation's coefficients become elements of the matrix.
- The matrix size is determined by the number of equations and variables, forming a square matrix in cases with equal numbers of both.
\[ \begin{bmatrix} 1 & a & 0 \ 0 & 1 & a \ a & 0 & 1 \end{bmatrix} \] This matrix form allows us to apply various techniques like finding determinants or using methods such as Gaussian elimination more straightforwardly. Such representation also helps in identifying properties like the zero determinant, leading to insights about the system's solutions.