Chapter 7: Problem 1
The diameter of a cylinder is measured using a Vernier callipers with no zero error. It is found that the zero of the Vernier scale lies between \(5.10 \mathrm{~cm}\) and \(5.15 \mathrm{~cm}\) of the main scale. The Vernier scale has 50 divisions equivalent to \(2.45 \mathrm{~cm}\). The \(24^{\text {th }}\) division of the Vernier scale exactly coincides with one of the main scale divisions. The diameter of the cylinder is (A) \(5.112 \mathrm{~cm}\) (B) \(5.124 \mathrm{~cm}\) (C) \(5.136 \mathrm{~cm}\) (D) \(5.148 \mathrm{~cm}\)
Short Answer
Step by step solution
Key Concepts
These are the key concepts you need to understand to accurately answer the question.