Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

A person can not see clearly an object kept at a distance beyond of \(100 \mathrm{~cm}\). Find the nature and the power of lens to be used for seeing clearly the object at infinity. \((1)-1 D\) (2) \(+1 D\) (3) \(-3 D\) (4) \(3 \mathrm{D}\)

Short Answer

Expert verified
The correct lens is a converging lens with power +1 D (option 2).

Step by step solution

01

- Understanding the Problem

The person's far point is at 100 cm, meaning they cannot see objects clearly beyond this distance. To correct their vision, a lens is needed to help them see objects at infinity.
02

- Identify the Far Point

The far point is the distance at which the person can see clearly, given as 100 cm or 1 meter.
03

- Use Lens Formula

The lens formula for determining the power of the lens required to make the far point at infinity is: \[P = \frac{1}{f} = \frac{1}{d_{far}}\]
04

- Calculate Power

Substitute the far point distance into the formula: \[P = \frac{1}{1 \text{ meter}} = +1 \text{ diopter}\]
05

- Determine the Nature of the Lens

A positive power indicates that a converging lens (convex lens) is needed to correct the vision.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Lens Formula
To solve many problems involving lenses, we use the lens formula. This formula relates the object distance \(u\), the image distance \(v\), and the focal length \(f\) of the lens. The lens formula is:

\[ \frac{1}{f} = \frac{1}{v} + \frac{1}{u} \]

When dealing with corrective lenses, we often use a simplified version of this formula:

\[ P = \frac{1}{f} \]

Here, \(P\) represents the power of the lens in diopters (D), and \(f\) is the focal length in meters. This formula is essential for understanding how different lenses either converge or diverge light to correct vision. For instance, in the context of the given exercise, the objective was to find the necessary lens power to enable a person to see distant objects sharply.
Diopter Calculation
The concept of diopters is used to measure the optical power of a lens. The formula is:

\[ P = \frac{1}{f \text{(in meters)}} \]

In our exercise, the person's far point is at 100 cm, or 1 meter. This means the focal length \(f\) of the corrective lens should be 1 meter. Plugging this into the formula gives us:

\[ P = \frac{1}{1} = +1 \text{D} \]

This calculation shows that the lens needed is \( +1 \text{diopter}\), indicating the lens's optical power necessary to correct the vision. A positive diopter value typically points to the use of a convex lens, which helps the eye focus on distant objects properly.
Convex Lens
A convex lens, also known as a converging lens, is thicker in the middle than at the edges. This shape causes light rays entering the lens to bend toward each other and converge at a point known as the focal point.

Convex lenses are widely used in various optical devices like magnifying glasses, cameras, and corrective lenses for people with farsightedness (hyperopia). These lenses help correct vision by converging light rays before they hit the eye, thereby assisting the eye in focusing on objects that are far away.

In our exercise, the lens required has a power of \( +1 \text{D}\). This indicates a convex lens because it needs to converge light rays to create a clear image of distant objects on the person's retina. So, whenever you see a positive diopter value in vision correction, think of a convex or converging lens, which aids in focusing on distant objects by bending the light rays inward.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

If \(f(x)=\left\\{\begin{array}{cl}x & , 0 \leq x \leq 1 \\ 2-e^{x-1}, & 1

STATEMENT-1 : A parallel beam of light traveling in air can be displaced laterally by a parallel transparent slab by distance more than the thickness of the plate. And STATEMENT-2 : The lateral displacement of light traveling in air increased with rise in value of refractive index of slab. (1) Statement- 1 is true, statement-2 is true and statement-2 is correct explanation for statement-1 (2) Statement-1 is true, statement-2 is true and statement-2 is NOT correct explanation for statement-1 (3) Statement-1 is true, statement-2 is false (4) Statement-1 is false, statement-2 is true

The \(660 \mathrm{~V}\) rails on a subway can kill a person upon contact. A \(10,000 \mathrm{~V}\) Van de Graff generator, however, will only give a mild shock. Which of the following best explains this seeming paradox ? (1) The generator provides more energy per charge, but since it has few charges it transfers a lesser amount of energy. (2) The generator provides more energy, but since there is little energy per charge the current is small. (3) Most of the energy provided by the generator is dissipated in the air because air presents a smaller resistance than the human body (4) Most of the energy flows directly to the ground without going through the human body since the generator is grounded.

Number of divisors of 240 in the form of \(4 n+2, n \in W\) is equal to (1) 4 (2) 8 (3) 10 (4) 3

A soap bubble (surface tension \(=T\) ) is charged to a maximum surface density of charge \(=\sigma\), when it is just going to burst. Its radius \(\mathrm{R}\) is given by: (1) \(\mathrm{R}=\frac{\sigma^{2}}{8 \varepsilon_{0} T}\) (2) \(\mathrm{R}=8 \varepsilon_{0} \frac{\mathrm{T}}{\sigma^{2}}\) (3) \(\mathrm{R}=\frac{\sigma}{\sqrt{8 \varepsilon_{0} T}}\) (4) \(R=\frac{\sqrt{8 \varepsilon_{0} T}}{\sigma}\)

See all solutions

Recommended explanations on English Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free