Chapter 7: Problem 62
\(\mathrm{KMnO}_{4}\) can be prepared from \(\mathrm{K}_{2} \mathrm{MnO}_{4}\) as per the reaction : \(3 \mathrm{MnO}_{4}^{2-}+2 \mathrm{H}_{2} \mathrm{O} \rightleftharpoons 2 \mathrm{MnO}_{4}^{-}+\mathrm{MnO}_{2}+4 \mathrm{OH}^{-}\) The reaction can go to completion by removing \(\mathrm{OH}^{-}\)ions by adding : (1) \(\mathrm{KOH}\) (2) \(\mathrm{CO}_{2}\) (3) \(\mathrm{SO}_{2}\) (4) \(\mathrm{HCl}\)
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