Chapter 3: Problem 39
The distance moved by the screw of a screw gauge is \(2 \mathrm{~mm}\) in four rotations and there are 50 divisions on its cap. When nothing is put between its jaws, \(30^{\text {th }}\) division of circular scale coincides with reference line, with zero of circular scale lying above the reference line. When a plate is placed between the jaws, main scale reads 2 division and circular scale reads 20 division. Thickness of plate is : (1) \(1.5 \mathrm{~mm}\) (2) \(1.2 \mathrm{~mm}\) (3) \(1.4 \mathrm{~mm}\) (4) \(1.6 \mathrm{~mm}\)
Short Answer
Step by step solution
- Calculate the Pitch
- Calculate the Least Count
- Determine the Zero Error
- Main Scale Reading (MSR)
- Circular Scale Reading (CSR)
- Calculate the Total Reading
- Determine the Corrected Reading
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
screw gauge
It consists of a main scale, a circular scale, and a rotating screw. The screw advances every time it completes a rotation, allowing precise measurements.
Screw gauges are often used in laboratories and workshops for accurate measurements.
pitch calculation
For example, if the screw moves 2 mm in 4 rotations, the pitch is calculated as:
\(\text{Pitch} = \frac{2 \text{ mm}}{4 \text{ rotations}} = 0.5 \text{ mm per rotation}\)
Understanding pitch is crucial for accurate screw gauge measurements.
least count determination
\(\text{Least Count} = \frac{\text{Pitch}}{\text{Number of divisions on the circular scale}}\)
In our example, if the pitch is 0.5 mm and there are 50 divisions on the circular scale:
\(\text{Least Count} = \frac{0.5 \text{ mm}}{50} = 0.01 \text{ mm}\)
This small unit allows for high precision in measurements.
zero error
In our example, the 30th division coincides with the reference line, and zero is above this line, indicating a negative zero error of:
\(\text{Zero Error} = -30 \times \text{Least Count} = -30 \times 0.01 = -0.3 \text{ mm}\)
Zero error must be corrected in the final measurement.
main scale reading
When a plate is placed between the jaws, the MSR in this example is 2 divisions, equivalent to 2 mm:
\(\text{MSR} = 2 \text{ mm}\)
This value contributes significantly to the total measurement.
circular scale reading
Each division represents a fraction of the pitch. In this case, if the circular scale reading is 20 divisions:
\(\text{CSR} = 20 \times \text{Least Count} = 20 \times 0.01 = 0.2 \text{ mm}\)
Combining CSR with MSR gives higher measurement precision.
corrected reading calculation
First, calculate the total reading:
\(\text{Total Reading} = \text{MSR} + \text{CSR} = 2 \text{ mm} + 0.2 \text{ mm} = 2.2 \text{ mm}\)
Then, adjust for zero error:
\(\text{Corrected Reading} = \text{Total Reading} - \text{Zero Error} = 2.2 \text{ mm} - (-0.3 \text{ mm}) = 2.2 \text{ mm} + 0.3 \text{ mm} = 2.5 \text{ mm}\)
Hence, the accurate thickness of the plate is 2.5 mm.