Quadratic equations are equations of the form \(ax^2 + bx + c = 0\). In this exercise, the quadratic equation given in Statement (1) is \(y^2 - y - 2 = 0\).
We solve quadratic equations by factoring, completing the square, or using the quadratic formula. For simplicity, we’ll focus on factoring in this exercise:
First, rewrite the equation as is and look for factors:
The given equation becomes \((y - 2)(y + 1) = 0\).
To find the solutions, set each factor equal to zero:
- \(y - 2 = 0\) implies \(y = 2\)
- \(y + 1 = 0\) implies \(y = -1\)
So, the solutions for \(y\) based on the quadratic equation are 2 and -1. This means \(y\) can be either a positive or a negative value.
Because one solution is positive and the other is negative, this statement alone isn't enough to determine if \(y\) is strictly negative.