Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

If \(x / y=199\), what percentage of \(x\) is \(x-y\) ? (A) 99 (B) 100 (C) 51 (D) 49 (E) Cannot be determined

Short Answer

Expert verified
(A) 99

Step by step solution

01

- Express given equation

The problem states that \ \( \frac{x}{y} = 199 \). This can be rewritten to express \ \( x \) in terms of \ \( y \). Therefore, \ \( x = 199y \).
02

- Substitute the value of x

Substitute the value of \ \( x \) into the expression \ \( x - y \). So, \ \( x - y = 199y - y = 198y \).
03

- Find percentage

Now, find what percentage \ \( 198y \) is of \ \( 199y \). Using the formula for percentage: \ \( \text{Percentage} = \left( \frac{198y}{199y} \right) \times 100 \).
04

- Simplify

The \ \( y \) terms cancel out in the fraction, so we are left with: \ \( \left( \frac{198}{199} \right) \times 100 \approx 99.5\% \).
05

- Look at the given choices

Among the given options, the closest one to \ \( 99.5\% \) is \ \text{(A) 99.} \ So, the correct answer is \text{(A) 99.}

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

GMAT math strategies
When solving GMAT math problems, particularly those involving percentages, a systematic approach is essential. Start by understanding the problem statement. Break it down to identify key information and reframe the problem in simpler terms. This problem, for example, involves finding the percentage of one quantity with respect to another.
You can utilize GMAT-specific strategies such as:
  • Rewriting equations to isolate variables
  • Substitution to simplify expressions
  • Elimination of variables when possible
Applying these strategies step by step can help arrive at the correct solution efficiently. In our problem, rewriting the original equation \(\frac{x}{y} = 199\) into \(x = 199y\) and then substituting this back into the expression makes it much easier to manage. Following this structured method ensures clarity and precision.
Percentage calculations
Percentages are a fundamental concept in GMAT math, requiring a good grasp of basic arithmetic. When given values like we see in the exercise, it's important to understand how to express one value as a percentage of another.
Here’s a simple formula to remember:
\(\text{Percentage} = \frac{\text{Part}}{\text{Whole}} \times 100\).
In our specific problem, we need to find what percentage \(x - y \), which is 198y, is of x, which is 199y. By substituting these values into our percentage formula, it becomes \(\frac{198y}{199y} \times 100\). The y terms cancel out, simplifying our calculation to \(\frac{198}{199} \times 100\), which approximates to 99.5%.
This method works universally for many GMAT percentage problems, ensuring accuracy and simplifying even complex percentage calculations.
Test-taking techniques
Mastering test-taking techniques can significantly enhance your performance on the GMAT. Here are several techniques useful for math sections:
  • Elimination: Quickly eliminate options that are clearly incorrect to narrow down your choices.
  • Estimation: For problems involving complex calculations, approximate values to see which option is closest.
  • Time Management: Allocate time wisely to ensure you complete all questions. Skip and return to complex problems if needed.
For the given problem, after calculating the value 99.5%, identify the answer choice that is nearest - Option (A) 99. Utilizing elimination and estimation, you can efficiently arrive at the correct choice. This way, even when exact calculations are challenging, you can confidently choose the closest approximation from the provided options.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

She warned the three individuals that they needed to take more care, otherwise they would loose their possessions. A. individuals that they needed to take more care, otherwise they would loose B. individuals that they needed to take more care, otherwise they would lose C. people that they needed to take more care, otherwise they would loose D. persons that they needed to take more care, otherwise they would loose E. people that they needed to take more care, otherwise they would lose

In the first few moments of the Big Bang, the universe consisted of only quarks and gluons. A. consisted of only B. consists only of C. consisting of only D. according to some physicists, consists of only E. according to some physicists, consisting only of

Is \(x\) positive or negative? (1) \(x^3+8=0\) (2) \(x^2-4=0\) A. 1 alone, not 2 alone B. 2 alone, not 1 alone C. 1 and 2 together (need both) D. 1 alone or 2 alone E. 1 and 2 together are not sufficient

The assessment of the Director was pessimistic ago two weeks. A. The assessment of the Director was pessimistic ago two weeks. B. The Director’s assessment was pessimistic before two weeks. C. Two weeks before the assessment of the Director was pessimistic. D. Two weeks ago the Director’s assessment is pessimistic. E. Two weeks ago the assessment of the Director was pessimistic.

Is \(\mathrm{x}^2>\mathrm{y}^2\) ? (1) \(x>y\) (2) \(x / y>0\) A. 1 alone, not 2 alone B. 2 alone, not 1 alone C. 1 and 2 together (need both) D. 1 alone or 2 alone E. 1 and 2 together are not sufficient

See all solutions

Recommended explanations on English Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free