Chapter 25: Problem 5
5\. Consider a game inspired by the long-running television program The Price Is Right. Three players have to guess the price \(x\) of an object. It is common knowledge that \(x\) is a random variable that is distributed uniformly over the integers \(1,2, \ldots, 9\). That is, with probability \(1 / 9\) the value of \(x\) is 1 , with probability \(1 / 9\) the value of \(x\) is 2 , and so on. Thus, each player guesses a number from the set \(\\{1,2,3,4,5,6,7,8,9\\}\). The game runs as follows: First, player 1 chooses a number \(n_{1} \in\\{1,2\), \(3,4,5,6,7,8,9\\}\), which the other players observe. Then player 2 chooses a number \(n_{2}\) that is observed by the other players. Player 2 is not allowed to select the number already chosen by player 1 ; that is, \(n_{2}\) must be different from \(n_{1}\). Player 3 then selects a number \(n_{3}\), where \(n_{3}\) must be different from \(n_{1}\) and \(n_{2}\). Finally, the number \(x\) is drawn and the player whose guess is closest to \(x\) without going over wins \(\$ 1000\); the other players get 0 . That is, the winner must have guessed \(x\) correctly or have guessed a lower number that is closest to \(x\). If all of the players' guesses are above \(x\), then everyone gets \(0 .\) (a) Suppose you are player 2 and you know that player 3 is sequentially rational. If player 1 selected \(n_{1}=1\), what number should you pick to maximize your expected payoff? (b) Again suppose you are player 2 and you know that player 3 is sequentially rational. If player 1 selected \(n_{1}=5\), what number should you pick to maximize your expected payoff? (c) Suppose you are player 1 and you know that the other two players are sequentially rational. What number should you pick to maximize your expected payoff?
Short Answer
Step by step solution
Key Concepts
These are the key concepts you need to understand to accurately answer the question.