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Consider a game between a police officer (player 3 ) and two drivers (players 1 and 2). Player 1 lives and drives in the Clairemont neighborhood of San Diego, whereas player 2 lives and drives in the Downtown area. On a given day, players 1 and 2 each have to decide whether or not to use their cell phones while driving. They are not friends, so they will not be calling each other. Thus, whether player 1 uses a cell phone is independent of whether player 2 uses a cell phone. Player 3 (the police officer) selects whether to patrol in Clairemont or Downtown. All of these choices are made simultaneously and independently. Note that the strategy spaces are \(S_{1}=\\{\mathrm{U}, \mathrm{N}\\}, S_{2}=\\{\mathrm{U}, \mathrm{N}\\}\), and \(S_{3}=\\{\mathrm{C}, \mathrm{D}\\}\), where "U" stands for "use cell phone," " \(\mathrm{N}\) " means "not use cell phone," "C"' stands for "Clairemont," and "D" means "Downtown." Suppose that using a cell phone while driving is illegal. Furthermore, if a driver uses a cell phone and player 3 patrols in his or her area (Clairemont for player 1, Downtown for player 2), then this driver is caught and punished. A driver will not be caught if player 3 patrols in the other neighborhood. A driver who does not use a cell phone gets a payoff of zero. A driver who uses a cell phone and is not caught obtains a payoff of 2 . Finally, a driver who uses a cell phone and is caught gets a payoff of \(-y\), where \(y>0\). Player 3 gets a payoff of 1 if she catches a driver using a cell phone, and she gets zero otherwise. (a) Does this game have a pure-strategy Nash equilibrium? If so, describe it. If not, explain why. (b) Suppose that \(y=1\). Calculate and describe a mixed-strategy equilibrium of this game. Explain whether people obey the law. (c) Suppose that \(y=3\). Calculate and describe a mixed-strategy equilibrium of this game. Explain whether people obey the law.

Short Answer

Expert verified
(a) No pure-strategy Nash equilibrium. (b) Mixed-equilibrium: drivers often disobey law when \(y=1\). (c) Mixed-equilibrium: better law compliance when \(y=3\).

Step by step solution

01

Analyze Pure-Strategy Nash Equilibrium (Part a)

To find a pure-strategy Nash equilibrium, we examine all possible strategies for the players. Consider the strategies: (1) both drivers not using the cell phone, police patrols either location; (2) both drivers use the cell phone and get caught; (3) one driver uses the cell phone and gets caught while another avoids. However, if both use the cell phone and get caught, they both receive negative payoffs, leading them to prefer strategies that bring non-negative payoffs. A pure strategy equilibrium doesn't exist since players will always find advantageous deviations.
02

Calculate Mixed-Strategy Equilibrium for y = 1 (Part b)

When the fine is 1, driver payoff when caught is -1. For player 1 to mix his strategies, his expected payoff from using a cell phone should equal not using it. Assuming the police patrol Clairemont with probability \(p\), and Downtown with probability \(1-p\), the payoff equations are: \[2(1-p) - 1(p) = 0\]For the police not to prefer Clairemont, the expected payoffs for both drivers must be equal. Similarly, the probability \(q\) of each driver using the phone could be determined by police outcomes: \(q = 2/3\). This makes both the police and drivers indifferent.
03

Analyze Implications for Obeying Law at y = 1 (Part b)

In this mixed-strategy equilibrium for \(y=1\), the probability of using a cell phone is significant (i.e., \(q = 2/3\)), which means drivers frequently disobey the law due to relatively low penalties.
04

Calculate Mixed-Strategy Equilibrium for y = 3 (Part c)

Now consider \(y=3\). When caught, drivers incur a payoff of -3. Adjusting the equation for the driver's decision using police probability \(p\): \[2(1-p) - 3p = 0\]Solving gives us \(p = 2/5\). Similarly, resolving for police choosing probabilities given driver choices (using mixed strategy balancing): \(q = 3/5\). Here, both drivers and police have balanced incentives.
05

Analyze Implications for Obeying Law at y = 3 (Part c)

With \(y = 3\) and \(q = 3/5\), the likelihood of using a phone decreases compared to \(y=1\), suggesting that higher penalties lead to increased law compliance.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Nash Equilibrium
In the game involving two drivers and a police officer, we explore the concept of Nash Equilibrium to determine if there exists a set of strategies where no player can benefit by changing their strategy, given the other players' strategies remain the same. A pure-strategy Nash Equilibrium occurs when each player chooses a single, non-random strategy. However, in this scenario, pure-strategy Nash Equilibrium does not exist.

Why? If both drivers decide to use their cell phones and end up getting caught by the police officer, they will face negative payoffs due to the fines. This negative outcome motivates them to change strategies to avoid such penalties. If instead both choose not to use cell phones, the police patrol choice is irrelevant to their payoff. Hence, there isn't a single strategy combination that benefits all in a manner that no player wants to deviate from. As a result, players continuously seek better outcomes, and a pure-strategy Nash Equilibrium fails to materialize.
Mixed-Strategy Equilibrium
When pure strategies do not stabilize as equilibrium points, we turn to mixed strategies. A mixed-strategy equilibrium involves players randomizing over their available strategies to make other players indifferent to their choices. Each player adjusts the probability of their various strategies to keep others from gaining a strategic advantage by changing their tactics.

In our game scenario, we calculated mixed-strategy equilibria for different penalties. For a fine (\(y = 1\)), players choose whether to use their phones or not based on the probability the police will patrol their area. The calculations show drivers use their phones with probability \(q = 2/3\), and police patrol Clairemont with probability \(p = 1/3\). When the fine increases to \(y = 3\), \(q = 3/5\) and \(p = 2/5\). Mixed-strategy equilibria ensure that each player's decision is optimized based on others' likely choices, maintaining a balance where players have no clear incentive to change their strategies.
  • Players are indifferent about using or not using a strategy when mixed-strategy equilibrium is achieved
  • Probabilities are adjusted based on the penalty's severity
Law Compliance
The main question is whether individuals follow the law based on the penalties for violations. By examining the mixed-strategy equilibria, we find that compliance levels correlate with the severity of the penalties.

For example, with a fine of \(y = 1\), drivers disobey the law more frequently, given the probability \(q = 2/3\) of using their phones. This low penalty demonstrates insufficient deterrence, as the benefits outweigh the potential costs. However, increasing the penalty to \(y = 3\) changes compliance behavior significantly. The probability of using a phone drops to \(q = 3/5\), showcasing a stronger adherence to legal regulations due to heightened penalties.
  • Higher fines reduce law violation probabilities
  • Efficient law enforcement complements penalty effects

The repercussions of penalties in game theory suggest that player behavior aligns more with law compliance when facing substantial consequences for illegal acts.

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Most popular questions from this chapter

Prove that every \(2 \times 2\) game has a Nash equilibrium (in either pure or mixed strategies). Do this by considering the following general game and breaking the analysis into two categories: (a) one of the pure-strategy profiles is a Nash equilibrium, and (b) none of the pure-strategy profiles is a Nash equilibrium.

Consider a game with \(n\) players. Simultaneously and independently, the players choose between \(\mathrm{X}\) and \(\mathrm{Y}\). That is, the strategy space for each player \(i\) is \(S_{i}=\\{\mathrm{X}, \mathrm{Y}\\}\). The payoff of each player who selects \(\mathrm{X}\) is \(2 m_{x}-m_{x}^{2}+3\), where \(m_{x}\) is the number of players who choose X. The payoff of each player who selects \(\mathrm{Y}\) is \(4-m_{y}\), where \(m_{y}\) is the number of players who choose \(\mathrm{Y}\). Note that \(m_{x}+m_{y}=n\). (a) For the case of \(n=2\), represent this game in the normal form and find the pure-strategy Nash equilibria (if any). (b) Suppose that \(n=3\). How many Nash equilibria does this game have? (Note: you are looking for pure-strategy equilibria here.) If your answer is more than zero, describe a Nash equilibrium. (c) Continue to assume that \(n=3\). Determine whether this game has a symmetric mixed-strategy Nash equilibrium in which each player selects \(\mathrm{X}\) with probability \(p\). If you can find such an equilibrium, what is \(p\) ?

Consider the following three-player team production problem. Simultaneously and independently, each player chooses between exerting effort (E) or not exerting effort ( \(N\) ). Exerting effort imposes a cost of 2 on the player who exerts effort. If two or more of the players exert effort, each player receives a benefit of 4 regardless of whether she herself exerted effort. Otherwise, each player receives zero benefit. The payoff to each player is her realized benefit less the cost of her effort (if she exerted effort). For instance, if player 1 selects \(\mathrm{N}\) and players 2 and 3 both select \(\mathrm{E}\), then the payoff vector is \((4,2,2)\). If player 1 selects \(E\) and players 2 and 3 both select \(N\), then the payoff vector is \((-2,0,0)\). (a) Is there a pure-strategy equilibrium in which all three players exert effort? Explain why or why not. (b) Find a symmetric mixed-strategy Nash equilibrium of this game. Let \(p\) denote the probability that an individual player selects \(\mathrm{N}\).

Player 1 (the "hider") and player 2 (the "seeker") play the following game. There are four boxes with lids, arranged in a straight line. For convenience, the boxes are labeled A, B, C, and D. The administrator of the game gives player 1 a \(\$ 100\) bill, and player 1 must hide it in one of the four boxes. Player 2 does not observe where player 1 hides the \(\$ 100\) bill. Once player 1 has hidden the bill, player 2 must open one (and only one) of the boxes. If the money is in the box that player 2 opens, then player 2 keeps the \(\$ 100\). If it is not, player 1 gets to keep the \(\$ 100\). (a) Does this game have a pure-strategy Nash equilibrium? (b) Find the mixed-strategy Nash equilibrium. (c) Suppose it is common knowledge that player 1 likes the letter "A" and would get extra satisfaction from putting the money in box A. Let this satisfaction be equivalent to receiving \(\$ 20\). Assume this is in addition to any money received in the game. How does player 1's preference for the letter "A" affect the equilibrium mixing probabilities? Calculate the new equilibrium strategy profile if you can. (d) Describe the equilibria of the game in which player 1's extra satisfaction from selecting box \(\mathrm{A}\) is equivalent to receiving \(\$ 120\).

Consider the following social problem. \({ }^{5}\) A pedestrian is hit by a car and lies injured on the road. There are \(n\) people in the vicinity of the accident. The injured pedestrian requires immediate medical attention, which will be forthcoming if at least one of the \(n\) people calls for help. Simultaneously and independently, each of the \(n\) bystanders decides whether or not to call for help (by dialing 911 on a cell phone or pay phone). Each bystander obtains \(v\) units of utility if someone (anyone) calls for help. Those who call for help pay a personal cost of \(c\). That is, if person \(i\) calls for help, then he obtains the payoff \(v-c\); if person \(i\) does not call but at least one other person calls, then person \(i\) gets \(v\); finally, if none of the \(n\) people calls for help, then person \(i\) obtains zero. Assume \(v>c\). (a) Find the symmetric Nash equilibrium of this \(n\)-player normal-form game. (Hint: The equilibrium is in mixed strategies. In your analysis, let \(p\) be the probability that a person does not call for help.) (b) Compute the probability that at least one person calls for help in equilibrium. (This is the probability that the injured pedestrian gets medical attention.) Note how this depends on \(n\). Is this a perverse or intuitive result?

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