Chapter 6: Problem 13
Proving the composite commodity theorem consists of showing that choices made when we use a composite commodity are identical to those that would be made if we specified the complete utility-maximization problem. This problem asks you to show this using two different approaches. For both of these we assume there are only three goods, \(x_{1}, x_{2},\) and \(x_{3}\) and that the prices of \(x_{2}\) and \(x_{3}\) always move together-that is, \(p_{2}=t p_{2}^{0}\) and \(p_{3}=t p_{3}^{0},\) where \(p_{2}^{0}\) and \(p_{3}^{0}\) are the initial prices of these two goods. With this notation, the composite commodity, \(y,\) is defined as $$y=p_{2}^{0} x_{2}+p_{3}^{0} x_{3}$$ a. Proof using duality. Let the expenditure function for the original three-good problem be given by \(E\left(p_{1}, p_{2}, p_{3}, \bar{U}\right)\) and consider the alternative expenditure minimization problem; Minimize \(p_{1} x_{1}+\) tys.t. \(U\left(x_{1}, x_{2}, x_{3}\right)=\bar{U}\). This problem will also yield an expenditure function of the form \(E^{*}\left(p_{1}, t, \bar{U}\right)\) i. Use the envelope theorem to show that $$\frac{\partial E}{\partial t}=\frac{\partial E^{*}}{\partial t}=y$$ This shows that the demand for the composite good \(y\) is the same under either approach. ii. Explain why the demand for \(x_{1}\) is also the same under either approach? (This proof is taken from Deaton and Muellbauer, \(1980 .)\) b. Proof using two- stage maximization. Now consider this problem from the perspective of utility maximization. The problem can be simplified by adopting the normalization that \(p_{2}=1-\) that is, all purchasing power is measured in units of \(x_{2}\) and the prices \(p_{1}\) and \(p_{3}\) are now treated as prices relative to \(p_{2}\). Under the assumptions of the composite commodity theorem, \(p_{1}\) can vary, but \(p_{3}\) is a fixed value. The original utility maximization problem is: \\[ \text { Maximize } U\left(x_{1}, x_{2}, x_{3}\right) \text { s.t. } p_{1} x_{1}+x_{2}+p_{3} x_{3}=M \\] (where \(M=I / p_{2}\) ) and the first-order conditions for a maximum are \(U_{i}=\lambda p_{i}, i=1,3\) (where \(\lambda\) is the Lagrange multiplier). The alternative, two-stage approach to the problem is \\[ \text { Stage } 1: \text { Maximize } U\left(x_{1}, x_{2}, x_{3}\right) \text { s.t. } x_{2}+p_{3} x_{3}=m \\] (where \(m\) is the portion of \(M\) devoted to purchasing the composite good). This maximization problem treats \(x_{1}\) as an exogenous parameter in the maximization process, so it becomes an element of the value function in this problem. The first-order conditions for this problem \(\operatorname{are} U_{i}=\mu p_{i}\) for \(i=2,3,\) where \(\mu\) is the Lagrange multiplier for this stage of the problem. Let the value (indirect utility) function for this stage 1 problem be given by \(V\left(x_{1}, m\right)\)The final part of this two-stage problem is then: \\[ \text { Stage } 2: \text { Maximize } V\left(x_{1}, m\right) \quad \text { s.t. } p_{1} x_{1}+m=M \\] This will have first-order conditions of the form \(\partial V / \partial x_{1}=\delta p_{1}\) and \(\partial V / \partial m=\delta,\) where \(\delta\) is the Lagrange multiplier for stage 2 Given this setup, answer the following questions: i. Explain why the value function in stage 1 depends only on \(x_{1}\) and \(m .\) (Hint: This is where the fact that \(p_{3}\) is constant plays a key role.) ii. Show that the two approaches to this maximization problem yield the same result by showing that \(\lambda=\mu=\delta .\) What do you have to assume to ensure the results are equivalent? (This problem is adapted from Carter, \(1995 .)\)
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Key Concepts
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