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Suppose a firm's total revenues depend on the amount produced \((q)\) according to the function \\[ R=70 q-q^{2} \\] Total costs also depend on \(q\) \\[ C=q^{2}+30 q+100 \\] a. What level of output should the firm produce to maximize profits \((R-C) ?\) What will profits be? b. Show that the second-order conditions for a maximum are satisfied at the output level found in part (a). c. Does the solution calculated here obey the "marginal revenue equals marginal cost" rule? Explain.

Short Answer

Expert verified
The profit-maximizing output level for the firm is 10 units, and the maximum profit is 100. The solution does obey the marginal revenue equals marginal cost rule.

Step by step solution

01

Define the profit function

Let's define the profit function by subtracting the total cost function from the total revenue function: \\[ π(q) = R(q) - C(q) = (70q - q^2) - (q^2 + 30q + 100) \\]
02

Simplify the profit function

Now, we need to simplify the profit function: \\[ π(q) = 70q - q^2 - q^2 - 30q - 100 = -2q^2 + 40q - 100 \\]
03

Find the first and second derivatives of the profit function

Next, we have to take the first and second derivatives of the profit function with respect to q: \\[ π'(q) = \frac{d}{dq}(-2q^2 + 40q - 100) = -4q + 40 \\] \\[ π''(q) = \frac{d}{dq}(-4q + 40) = -4 \\]
04

Solve for the profit-maximizing output level

To find the profit-maximizing output level, we need to solve for q when the first derivative of the profit function is zero: \\[ π'(q) = -4q + 40 = 0 \\] Solving this equation, we get: \\[ q = 10 \\]
05

Check the second-order conditions for a maximum

Now, we need to check the second-order conditions to ensure that we have found a maximum. Since the second derivative, π''(q), is negative, it means that the profit function is concave down, which indicates a maximum at q = 10.
06

Calculate the maximum profit

To find the maximum profit, we plug the profit-maximizing output level into the profit function: \\[ π(10) = -2(10)^2 + 40(10) - 100 = -2(100) + 400 - 100 = -200 + 400 - 100 = 100 \\] So, the maximum profit is 100.
07

Verify the marginal revenue equals marginal cost rule

Let's find the marginal revenue and marginal cost functions by differentiating the total revenue and total cost functions with respect to q: Marginal Revenue (MR): \\[ MR = \frac{d}{dq}(70q - q^2) = 70 - 2q \\] Marginal Cost (MC): \\[ MC = \frac{d}{dq}(q^2 + 30q + 100) = 2q + 30 \\] Now, we need to check if marginal revenue equals marginal cost at the profit-maximizing output level (q = 10): \\[ MR(10) = 70 - 2(10) = 70 - 20 = 50 \\] \\[ MC(10) = 2(10) + 30 = 20 + 30 = 50 \\] Since MR(10) = MC(10), the solution obeys the marginal revenue equals marginal cost rule. #Conclusion# The firm should produce 10 units of output to maximize profits, and the maximum profit will be 100. The second-order conditions for a maximum are satisfied, and the solution obeys the marginal revenue equals marginal cost rule.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Marginal Revenue
Marginal Revenue (MR) is a measure of how much extra revenue a firm receives when it sells one additional unit of a product. In microeconomics, MR is crucial for understanding the profitability of increasing output. It can be determined by differentiating the total revenue (TR) function with respect to quantity (q). For example, if a firm's total revenue is represented by the function R = 70q - q2, the MR would be calculated as MR = \(\frac{dR}{dq}\) = 70 - 2q. What's important to note is that a profit-maximizing firm will continue to produce more as long as MR exceeds Marginal Cost (MC); it stops when MR equals MC, which is known as the profit-maximizing output level.
Marginal Cost
Marginal Cost (MC) represents the additional cost incurred by producing one more unit of a good. It's a fundamental concept as it helps businesses decide whether they should increase production. MC can be found by taking the derivative of the Total Cost (TC) function concerning quantity. In our example, the TC function is C = q2 + 30q + 100, so the MC would be MC = \(\frac{dC}{dq}\) = 2q + 30. A firm's goal to maximize profits is reached at the output level where MC exactly equals MR, indicating no advantage in producing additional units beyond this point.
Second-order Conditions
Second-order conditions refer to the criteria used in calculus to determine whether a found critical point (where the first derivative equals zero) is a maximum or a minimum. For a profit function, if the second derivative is negative at a particular output level, it signifies that the profit function is concave down, and thus, a maximum profit is achieved. In our exercise, after taking the first derivative of the profit function π'(q) and finding the profit-maximizing output, we determine the second derivative π''(q). Since π''(q) = -4 is negative, the second-order condition confirms we have a maximum profit at that output level.
Profit Function
The Profit Function expresses the total profit (π) a firm can make, calculated as the difference between Total Revenue (R) and Total Costs (C). It's defined as π(q) = R(q) - C(q). A firm aims to maximize its profit by adjusting its output levels. When we derive the profit function as illustrated in our example, with π(q) = 70q - q2 - q2 - 30q - 100, we seek the quantity that maximizes it. Determining where its first derivative is zero (and the second derivative is negative) guides us to the profit-maximizing output. Here, calculating the output at q = 10, results in the maximum profit of 100.

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Most popular questions from this chapter

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