Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

If \(A\) is an \(m \times n\) matrix, let \(C_{k}(A)\) denote column \(k\) of \(A .\) Show that \(C_{k}: \mathbf{M}_{m n} \rightarrow \mathbb{R}^{m}\) is a linear transformation for each \(k=1, \ldots, n\)

Short Answer

Expert verified
\(C_k: \mathbf{M}_{m\times n} \rightarrow \mathbb{R}^m\) is a linear transformation because it satisfies linearity properties.

Step by step solution

01

Understand the Problem

We are given a matrix function that takes a column from an \(m \times n\) matrix \(A\) and outputs an \(m\)-dimensional vector. Our goal is to show that this function is a linear transformation.
02

Define Linear Transformation

A function \(T: V \to W\) is a linear transformation if for all vectors \(u, v \in V\) and scalars \(c, d \in \mathbb{R}\), it holds that \(T(cu + dv) = cT(u) + dT(v)\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Matrix Functions
A matrix function, like the one given in the exercise, maps one set of matrices to another. In this case, our function maps an entire matrix to one of its columns.
Imagine you have a matrix full of numbers, and each number sits in its own little box; the columns and rows create a big grid of these boxes. When we say "matrix functions," we're talking about operations that can do things like change the size of the matrix, rearrange the elements, or focus on a specific part, such as a column, and pick it out.

In the exercise, the matrix function we're focusing on, denoted by \(C_k(A)\), picks out the \(k\)-th column of the matrix \(A\). This is a simple but very useful operation in linear algebra because columns can represent vectors. Therefore, taking out a column can help us do calculations with the vectors directly.
  • Column functions are straightforward: they take a vertical slice (a column) of the matrix.
  • These functions transform a 2D matrix into a 1D vector.
This kind of extraction is foundational when dealing with more complex matrix operations and is a building block for understanding how linear transformations work in linear algebra.
Linear Algebra
Linear algebra is the branch of mathematics that deals with vectors, vector spaces, and linear transformations. It's a powerful tool used in various fields like computer science, physics, and engineering. One of its fundamental concepts is the study of how we can represent and manipulate linear systems.

In our exercise, we're particularly dealing with linear transformations. These transformations map vectors from one space to another in a linear fashion. This simply means that when you apply the transformation to a combination of vectors and scale them, you can predict the outcome exactly based on the same combination and scale of their images.
  • A function is a linear transformation if it preserves scalar multiplication and addition.
  • This means that the structure stays consistent through transformation.
The function \(C_k\) in our problem illustrates this concept perfectly. It takes a whole matrix and outputs a single column vector, maintaining the properties of linearity. This is what makes linear algebra such a vital area of study: understanding these transformations helps us solve both simple systems and complex real-world problems.
Vector Spaces
Vector spaces are the setting for most of the work done in linear algebra. They are collections of vectors that are closed under vector addition and scalar multiplication. Think of vector spaces as playgrounds where vectors can act and interact without leaving the space.

In our exercise, the result of the matrix function \(C_k\) is a vector from a vector space \(\mathbb{R}^m\). This means the output of this function behaves as part of a set that's closed for the operations defined in vector spaces.
  • Each vector space has a defined dimension, which tells us how many vectors are needed to form the space.
  • Vectors in this space can be manipulated under the rules of linear transformations.
Understanding vector spaces helps you know the extent and limitations of transformations. It's crucial because they tell us how transformations like \(C_k\) maintain the integrity of data when operating within the rules of linear algebra. Vector spaces allow for the elegant and efficient handling of problems, making the combinations and resolutions systematic and predictable.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Show that the following conditions are equivalent for a linear transformation \(T: \mathbf{M}_{22} \rightarrow \mathbf{M}_{22}\). 1\. \(\operatorname{tr}[T(A)]=\operatorname{tr} A\) for all \(A\) in \(\mathbf{M}_{22}\). $$ \text { 2. } T\left[\begin{array}{ll} r_{11} & r_{12} \\ r_{21} & r_{22} \end{array}\right]=r_{11} B_{11}+r_{12} B_{12}+r_{21} B_{21}+ $$ \(r_{22} B_{22}\) for matrices \(B_{i j}\) such that \(\operatorname{tr} B_{11}=1=\operatorname{tr} B_{22}\) and \(\operatorname{tr} B_{12}=0=\operatorname{tr} B_{21}\)

Let \(A\) be an \(m \times n\) matrix of \(\operatorname{rank} r\) Thinking of \(\mathbb{R}^{n}\) as rows, define \(V=\left\\{\mathbf{x}\right.\) in \(\left.\mathbb{R}^{m} \mid \mathbf{x} A=\mathbf{0}\right\\}\). Show that \(\operatorname{dim} V=m-r\).

Let \(T: V \rightarrow V\) be a linear transformation such that \(T^{2}=0\) is the zero transformation. a. If \(V \neq\\{\mathbf{0}\\}\), show that \(T\) cannot be invertible. b. If \(R: V \rightarrow V\) is defined by \(R(\mathbf{v})=\mathbf{v}+T(\mathbf{v})\) for all \(\mathbf{v}\) in \(V\), show that \(R\) is linear and invertible.

Consider $$ V=\left\\{\left[\begin{array}{ll} a & b \\ c & d \end{array}\right] \mid a+c=b+d\right\\} $$ a. Consider \(S: \mathbf{M}_{22} \rightarrow \mathbb{R}\) with \(S\left[\begin{array}{cc}a & b \\ c & d\end{array}\right]=a+c-\) \(b-d\). Show that \(S\) is linear and onto and that \(V\) is a subspace of \(\mathbf{M}_{22}\). Compute \(\operatorname{dim} V\). b. Consider \(T: V \rightarrow \mathbb{R}\) with \(T\left[\begin{array}{ll}a & b \\\ c & d\end{array}\right]=a+c\). Show that \(T\) is linear and onto, and use this information to compute \(\operatorname{dim}(\) ker \(T)\).

Describe all linear transformations \(T: \mathbb{R} \rightarrow V\).

See all solutions

Recommended explanations on Economics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free