Chapter 5: Problem 7
Let \(\lambda\) be an eigenvalue of \(A\) with corresponding eigenvector \(\mathbf{x}\). If \(B=P^{-1} A P\) is similar to \(A\), show that \(P^{-1} \mathbf{x}\) is an eigenvector of \(B\) corresponding to \(\lambda\)
Short Answer
Expert verified
\( P^{-1} \mathbf{x} \) is an eigenvector of \( B \) with eigenvalue \( \lambda \).
Step by step solution
01
Understanding the Similarity
Matrix \( B \) is similar to \( A \), meaning \( B = P^{-1} A P \), where \( P \) is an invertible matrix. This similarity implies that \( A \) and \( B \) have the same eigenvalues. Therefore, if \( \lambda \) is an eigenvalue of \( A \), it is also an eigenvalue of \( B \).
02
Eigenvector Relationship for A
Given that \( \lambda \) is an eigenvalue of \( A \) with corresponding eigenvector \( \mathbf{x} \), we have the equation \( A \mathbf{x} = \lambda \mathbf{x} \).
03
Applying Similarity Transformation
By the properties of similar matrices, substituting \( A \) in terms of \( B \), we have \( A = P B P^{-1} \). Using this, and given \( A \mathbf{x} = \lambda \mathbf{x} \), we can express \( A \mathbf{x} = \lambda \mathbf{x} \) as \( P B P^{-1} \mathbf{x} = \lambda \mathbf{x} \).
04
Transforming the Eigenvector
Let \( \mathbf{y} = P^{-1} \mathbf{x} \). Then, the equation \( P B \mathbf{y} = \lambda P \mathbf{y} \) can be derived from substituting \( \mathbf{y} \) in Step 3, which simplifies to \( B \mathbf{y} = \lambda \mathbf{y} \) because \( P \) is invertible, canceling with its inverse.
05
Conclusion of Eigenvector for B
From the equation \( B \mathbf{y} = \lambda \mathbf{y} \), it follows that \( \mathbf{y} = P^{-1} \mathbf{x} \) is an eigenvector of \( B \) corresponding to eigenvalue \( \lambda \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Matrix Similarity
Matrix similarity is an important concept in linear algebra that helps us understand how matrices relate to each other. Two matrices, say \( A \) and \( B \), are said to be similar if there exists an invertible matrix \( P \) such that \( B = P^{-1} A P \). Similar matrices share several key properties:
- They have the same eigenvalues, although their eigenvectors may differ.
- Since they represent the same linear transformation in different bases, we can think of similarity as a way of translating one matrix into another form that might be easier to understand or compute with.
- Similarity preserves the determinant and trace of the matrices, meaning these values remain unchanged as well.
Linear Transformation
A linear transformation is a fundamental concept in linear algebra, representing a function between two vector spaces that preserves the operations of vector addition and scalar multiplication. When considering a matrix \( A \), applying \( A \) to a vector \( \mathbf{x} \) in a vector space \( V \) results in another vector in \( V \):
- This operation is often written as \( A \mathbf{x} \), representing how \( A \) transforms \( \mathbf{x} \).
- The matrix \( A \) itself can be seen as providing the instructions for this transformation.
- Linear transformations can be rotations, reflections, scaling, or any combination of these.
Invertible Matrix
An invertible matrix, also known as a non-singular or non-degenerate matrix, has a crucial property: it can be reversed. Specifically, a square matrix \( P \) is invertible if there exists another matrix \( P^{-1} \) such that:
- \( P P^{-1} = P^{-1} P = I \), where \( I \) is the identity matrix.
- The identity matrix \( I \) serves as the multiplicative identity in matrix algebra, having the property that multiplying any matrix by \( I \) leaves the original matrix unchanged.
- An invertible matrix has a non-zero determinant, making its inverse well-defined.