Chapter 3: Problem 5
How many "words" of \(k\) letters can be made from the letters \(\\{a, b\\}\) if there are no adjacent \(a\) 's?
Short Answer
Expert verified
The number of such words is given by the \((k+2)\)th Fibonacci number.
Step by step solution
01
Understand the Problem
You need to count how many sequences ("words") of length \(k\) can be formed using the letters \(\{a, b\}\) such that no two \('a'\) letters are next to each other.
02
Define the Base Cases
For \(k = 1\), the possible words are \('a'\) and \('b'\), yielding 2 words in total.
03
Use Recursion for Larger k
We need a recursive way to build solutions. Let \(a_k\) be the count of valid words of length \(k\). We'll split this into two parts: ending with 'a' and ending with 'b'. If a word of length \(k\) ends with 'a', then the previous letter must be 'b', making it \(b_{k-1}\). If it ends with 'b', it could be either a valid word of length \(k-1\) followed by 'b', i.e., \(a_{k-1}\). So, the recurrence relation is \(a_k = a_{k-1} + b_{k-1}\) and \(b_k = a_k\).
04
Simplify the Recurrence Relation
Recognizing that \(b_k = a_k\), we simplify it to: \(a_k = a_{k-1} + a_{k-2}\). This is the Fibonacci sequence, where \(F_1 = 2\) and \(F_2 = 3\) to start.
05
Calculate Through Iteration
Consider the base case for \(k=1\): \(a_1 = 2\). For \(k=2\): \(a_2 = 3\). Further calculations follow the Fibonacci sequence incrementing from these initial conditions. For example, \(a_3 = a_2 + a_1 = 3 + 2 = 5\). Continue this for larger \(k\).
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with Vaia!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Fibonacci sequence
The Fibonacci sequence is a famous number sequence where each number is the sum of the two preceding ones, typically starting with 0 and 1. In mathematical terms, it's expressed as:
- \( F_0 = 0 \)
- \( F_1 = 1 \)
- \( F_n = F_{n-1} + F_{n-2} \text{ for } n > 1 \)
Recurrence relations
Recurrence relations are equations that recursively define sequences. By describing each term as a function of the preceding ones, they help solve complex combinatorial problems succinctly. They are foundational in computer science, especially for algorithms involving iterative calculations, like sorting algorithms or dynamic programming.In our exercise, the problem involves finding a relation that defines the number of valid words, given the constraints. We derived:
- \( a_k = a_{k-1} + a_{k-2} \)
Base cases
Base cases are crucial in recursive problems. They define the simplest instances, serving as the foundation for building more complex solutions. Without them, a recursive approach lacks a starting point, which can result in endless calculations.In our exercise, the base cases are:
- For \( k = 1 \), there are two words: 'a' and 'b'. Hence, \( a_1 = 2 \).
- For \( k = 2 \), the valid words are 'ab' and 'ba'. Thus, \( a_2 = 3 \).