Chapter 3: Problem 5
\(\begin{array}{lll}\text { Exercise } & \mathbf{3 . 3 . 5} & \text { Show that the eigenvalues of }\end{array}\) \(\left[\begin{array}{cc}\cos \theta & -\sin \theta \\ \sin \theta & \cos \theta\end{array}\right]\) are \(e^{i \theta}\) and \(e^{-i \theta} .\) (See Appendix A)
Short Answer
Expert verified
The eigenvalues are \(e^{i\theta}\) and \(e^{-i\theta}\).
Step by step solution
01
Understanding the Matrix and Eigenvalues
The given matrix is a rotation matrix:\[A = \begin{bmatrix}\cos \theta & -\sin \theta \ \sin \theta & \cos \theta\end{bmatrix}\]We need to find its eigenvalues, which are scalars \( \lambda \) satisfying the equation \( \det(A - \lambda I) = 0 \).
02
Writing Down the Characteristic Equation
The characteristic equation is\[\det(\begin{bmatrix}\cos \theta & -\sin \theta \ \sin \theta & \cos \theta\end{bmatrix} - \lambda \begin{bmatrix}1 & 0 \ 0 & 1 \end{bmatrix}) = 0\]This expands to\[\det(\begin{bmatrix}\cos \theta - \lambda & -\sin \theta \ \sin \theta & \cos \theta - \lambda \end{bmatrix}) = 0\]
03
Computing the Determinant
We compute the determinant:\[(\cos \theta - \lambda)(\cos \theta - \lambda) - (-\sin \theta)(\sin \theta) = 0\]Simplifying, we get:\[(\cos \theta - \lambda)^2 + \sin^2 \theta = 0\]
04
Simplifying the Equation
Combine and simplify:\[\lambda^2 - 2\lambda \cos\theta + \cos^2\theta + \sin^2\theta = 0\]Using \( \cos^2 \theta + \sin^2 \theta = 1 \), we get:\[\lambda^2 - 2\lambda \cos\theta + 1 = 0\]
05
Solving the Quadratic Equation
Solve the quadratic equation \( \lambda^2 - 2\lambda \cos\theta + 1 = 0 \) using the quadratic formula:\[\lambda = \frac{2\cos\theta \pm \sqrt{(2\cos\theta)^2 - 4}}{2}\]Simplifying gives:\[\lambda = \cos \theta \pm \sqrt{\cos^2\theta - 1}\]
06
Applying Complex Roots Simplification
Recognize that the term \( \sqrt{\cos^2\theta - 1} \) simplifies to \( i\sin\theta \), since \( \cos^2\theta - 1 = -\sin^2\theta \):\[\lambda = \cos \theta \pm i\sin\theta\]
07
Verifying the Complex Exponential Form
Recall Euler’s formula \( e^{i \theta} = \cos \theta + i\sin \theta \), thus:\[\lambda_1 = e^{i\theta}, \quad \lambda_2 = e^{-i\theta}\]
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Rotation Matrices
Rotation matrices are fundamental in linear algebra used to rotate vectors in a plane. The general form of a 2D rotation matrix is:
It's important to understand that these matrices preserve lengths and angles, making them orthogonal, with a determinant of 1. This feature ensures that the rotation itself is rigid, i.e., it doesn't stretch or compress the original vector.
- \[A = \begin{bmatrix} \cos \theta & -\sin \theta \ \sin \theta & \cos \theta \end{bmatrix}\]
It's important to understand that these matrices preserve lengths and angles, making them orthogonal, with a determinant of 1. This feature ensures that the rotation itself is rigid, i.e., it doesn't stretch or compress the original vector.
Characteristic Equation
The characteristic equation is central to finding the eigenvalues of a matrix. This involves the determinant of the matrix subtracted by the product of a variable, \( \lambda \), and an identity matrix. Formally, for a matrix \( A \), the characteristic equation is given by:
In the context of rotation matrices, solving this quadratic gives insight into the behavior of the transformation applied by the matrix.
- \[\det(A - \lambda I) = 0\]
In the context of rotation matrices, solving this quadratic gives insight into the behavior of the transformation applied by the matrix.
Complex Numbers
Complex numbers are crucial when solving problems involving rotations, especially when the solutions involve imaginary components. A complex number is expressed as:
For rotation matrices, the appearance of complex numbers is linked to the trigonometric identities and Pythagorean identities that govern the functions sine and cosine. When solving for the eigenvalues of a rotation matrix, the real and imaginary parts reflect the cosine and sine terms in the corresponding expressions, ultimately vital for expressing the eigenvalues in exponential form via Euler's formula.
- \[a + bi\]
For rotation matrices, the appearance of complex numbers is linked to the trigonometric identities and Pythagorean identities that govern the functions sine and cosine. When solving for the eigenvalues of a rotation matrix, the real and imaginary parts reflect the cosine and sine terms in the corresponding expressions, ultimately vital for expressing the eigenvalues in exponential form via Euler's formula.
Euler's Formula
Euler's formula elegantly bridges complex numbers and trigonometry, showing the close relationship between exponential and trigonometric functions. It is expressed as:
Euler’s formula facilitates converting the eigenvalues derived from the characteristic equation into a simpler form that uses the exponential function. This conversion helps solve problems involving wave functions, oscillations, and quantum mechanics. In the case of the rotation matrix, the eigenvalues \( e^{i\theta} \) and \( e^{-i\theta} \) align with Euler's formula, highlighting the deep connection between rotations and exponential growth.
- \[e^{i\theta} = \cos \theta + i\sin \theta\]
Euler’s formula facilitates converting the eigenvalues derived from the characteristic equation into a simpler form that uses the exponential function. This conversion helps solve problems involving wave functions, oscillations, and quantum mechanics. In the case of the rotation matrix, the eigenvalues \( e^{i\theta} \) and \( e^{-i\theta} \) align with Euler's formula, highlighting the deep connection between rotations and exponential growth.