Chapter 3: Problem 2
Use determinants to find which real values of \(c\) make each of the following matrices invertible. a. \(\left[\begin{array}{rrr}1 & 0 & 3 \\ 3 & -4 & c \\ 2 & 5 & 8\end{array}\right]\) b. \(\left[\begin{array}{rrr}0 & c & -c \\ -1 & 2 & 1 \\ c & -c & c\end{array}\right]\) c. \(\left[\begin{array}{rrr}c & 1 & 0 \\ 0 & 2 & c \\ -1 & c & 5\end{array}\right]\) d. \(\left[\begin{array}{lll}4 & c & 3 \\ c & 2 & c \\ 5 & c & 4\end{array}\right]\) e. \(\left[\begin{array}{rrr}1 & 2 & -1 \\ 0 & -1 & c \\ 2 & c & 1\end{array}\right]\) f. \(\left[\begin{array}{rrr}1 & c & -1 \\ c & 1 & 1 \\ 0 & 1 & c\end{array}\right]\)
Short Answer
Step by step solution
Understand Matrix Invertibility Using Determinants
Step 2a: Calculate Determinant for Matrix (a)
Step 2b: Calculate Determinant for Matrix (b)
Step 2c: Calculate Determinant for Matrix (c)
Step 2d: Calculate Determinant for Matrix (d)
Step 2e: Calculate Determinant for Matrix (e)
Step 2f: Calculate Determinant for Matrix (f)
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with Vaia!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Determinants
Real Values of c
- For Matrix (a): The determinant is calculated as \(19 - 5c\). To ensure invertibility, set \(19 - 5c eq 0\) yielding \(c eq \frac{19}{5}\).
- For Matrix (b): The determinant is \(5c^2\). Thus, \(c eq 0\) since any non-zero value ensures invertibility.
- For Matrix (c): The determinant becomes \(10c\). Hence, \(c eq 0\) for invertibility.