Chapter 10: Problem 2
Let \(T: \mathbb{R}^{2} \rightarrow \mathbb{R}^{2}\) be given by $$ T(a, b)=(2 a+b, a-b) $$ a. Show that \(T\) is symmetric if the dot product is used. b. Show that \(T\) is not symmetric if \(\langle\mathbf{x}, \mathbf{y}\rangle=\mathbf{x} A \mathbf{y}^{T},\) $$ \text { where } A=\left[\begin{array}{ll} 1 & 1 \\ 1 & 2 \end{array}\right] $$
Short Answer
Step by step solution
Recall the Definition of Symmetry
Verify Symmetry with Dot Product
Recall Alternate Inner Product Definition
Check Non-Symmetry with Alternate Product
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Symmetric Transformations
Applying this definition helps in understanding how transformations behave and ensures that the transformation preserves the symmetrical properties characterized by the dot product. In simpler terms, this condition ensures the angle and length relationships between vectors are preserved under the transformation.
Dot Product
- Commutative: \(\mathbf{a} \cdot \mathbf{b} = \mathbf{b} \cdot \mathbf{a}\)
- Distributive over addition: \(\mathbf{a} \cdot (\mathbf{b} + \mathbf{c}) = \mathbf{a} \cdot \mathbf{b} + \mathbf{a} \cdot \mathbf{c}\)
- Scalar multiplication compatibility: \((k\mathbf{a}) \cdot \mathbf{b} = k(\mathbf{a} \cdot \mathbf{b})\)
Matrix Multiplication
When associating matrices with transformations, you multiply matrices in the order of the transformation sequence:
\[ (AB)C = A(BC) \]
This operation is not commutative, meaning \(AB eq BA\) in general. Understanding matrix multiplication helps in finding out how different transformations stack together and affect vectors in a space, making it crucial for topics like linear transformations and other advanced linear algebra concepts.
Inner Product Spaces
- Conjugate symmetry: \(\langle \mathbf{x}, \mathbf{y} \rangle = \overline{\langle \mathbf{y}, \mathbf{x} \rangle}\)
- Linearity in the first argument: \(\langle a\mathbf{x} + b\mathbf{y}, \mathbf{z} \rangle = a\langle \mathbf{x}, \mathbf{z} \rangle + b\langle \mathbf{y}, \mathbf{z} \rangle \)
- Positive-definiteness: \(\langle \mathbf{x}, \mathbf{x} \rangle \geq 0\) with equality if and only if \(\mathbf{x} = 0\)