Chapter 3: Problem 3
Find \(Y=\) and \(C^{*}\) from the following: \\[ \begin{array}{l} Y=C+1_{0}+C_{0} \\ C=25+6 Y^{1 / 2} \\ l_{0}=16 \\ C_{0}=14 \end{array} \\]
Short Answer
Expert verified
\( Y = 121 \) and \( C^{*} = 91 \).
Step by step solution
01
Simplify the Equation for Y
Rearrange the equation for total output Y: given that \( Y = C + I_0 + C_0 \), we substitute the values of \( I_0 \) and \( C_0 \). This gives us: \[ Y = C + 16 + 14 \] Therefore, simplify it to: \[ Y = C + 30 \]
02
Substitute C into the Y Equation
Now substitute \( C = 25 + 6Y^{1/2} \) into the simplified equation from Step 1: \[ Y = (25 + 6Y^{1/2}) + 30 \] Simplify further: \[ Y = 55 + 6Y^{1/2} \]
03
Isolate and Simplify
Isolate both terms containing \(Y\): \[ Y - 6Y^{1/2} = 55 \]
04
Substitute and Solve Quadratically
Now, let \( x = Y^{1/2} \), implying \( x^2 = Y \). Substitute to obtain: \[ x^2 - 6x = 55 \] Rearrange the equation: \[ x^2 - 6x - 55 = 0 \] Use the quadratic formula \( x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \) to solve: Plug in values: \( a = 1, b = -6, c = -55 \) \[ x = \frac{-(-6) \pm \sqrt{(-6)^2 - 4 \cdot 1 \cdot (-55)}}{2 \cdot 1} \] \[ x = \frac{6 \pm \sqrt{36 + 220}}{2} \] \[ x = \frac{6 \pm \sqrt{256}}{2} \] \[ x = \frac{6 \pm 16}{2} \], yielding solutions \( x = 11 \) and \( x = -5 \). Discard \( x = -5 \) since a square root cannot be negative.
05
Find Y
Review \( x = 11 \) which was \( Y^{1/2} \); find \( Y \) as \( x^2 \): \[ Y = 11^2 = 121 \] Hence, \( Y = 121 \).
06
Calculate C^{*}
Now, substitute \( Y = 121 \) back into the consumption equation \( C = 25 + 6Y^{1/2} \): \[ C = 25 + 6 \cdot 11 = 25 + 66 = 91 \]. Therefore, \( C^{*} = 91 \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Quadratic Equations
Quadratic equations are a fundamental part of mathematics, appearing frequently in various applications, including those in economics. A quadratic equation is typically in the form \( ax^2 + bx + c = 0 \), where **a**, **b**, and **c** are constants, and \( x \) represents an unknown variable. The solution to this equation provides the value(s) of \( x \) which makes the equation true. To solve it, you can use the quadratic formula:
- \( x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \)
Economic Modeling
Economic modeling refers to the creation of abstract representations of economic processes. These models help in understanding, explaining, and predicting economic behaviors. Economic models often use mathematical equations to express relationships between different economic variables and assumptions. In the context of our exercise, the model expressed how consumption \( C \), investment \( I_0 \), and autonomous consumption \( C_0 \) relate to output \( Y \).
- Output Equation: \( Y = C + I_0 + C_0 \)
- Consumption Equation: \( C = 25 + 6 Y^{1/2} \)
Consumption Function
The consumption function is an economic concept that depicts the relationship between total consumption and total income in an economy. It shows how households' consumption levels change with variations in their income. The function can take many forms, but in our exercise, it is represented as:
- \( C = 25 + 6 Y^{1/2} \)
Output Equation
The output equation in economic modeling links the output of an economy or a firm to various inputs. It represents the total amount of goods and services produced, combining factors such as consumption, investment, and autonomous consumption. In this exercise, the output equation is given by:
- \( Y = C + I_0 + C_0 \)
- With specific values, \( Y = C + 16 + 14 = C + 30 \)