Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Give all possible values of \(x\) that can result from executing (define \(x\) 10) (parallel-execute (lambda () (set! \(x(* x x))\) ) (lambda () (set! \(x(* x x x))\) )) Which of these possibilities remain if we instead use serialized procedures: (define \(x\) 10) (define s (make-serializer)) (parallel-execute (s (lambda () (set! \(x(* x x))\) )) )) (s (lambda () (set! \(x(* x x x))\) )

Short Answer

Expert verified
Parallel execution: possible results are 100, 1000, or 1000000. Serialized execution: the result is 1000000.

Step by step solution

01

Understanding Parallel Execution

Parallel execution allows multiple processes to run simultaneously. In this exercise, there are two operations executed in parallel: squaring the variable \(x\) and cubing the variable \(x\). Because these two operations are being executed at the same time, the order of their execution is non-deterministic, meaning either one could complete before the other.
02

Calculating Squaring Operation

The first operation is to square the variable \(x\): \(x = x^2\). Initially, \(x\) is set to 10, so if this operation executes first, we have \(x = 10^2 = 100\).
03

Calculating Cubing Operation

The second operation is to cube the variable \(x\): \(x = x^3\). Initially, \(x\) is 10, so if this operation executes first, we have \(x = 10^3 = 1000\).
04

Analyzing Parallel Outcomes

The parallel execution might result in different values of \(x\):1. If cubing happens first, \(x\) becomes 1000, then the squaring operation might read 1000 and square it, resulting in \(x = (1000)^2 = 1000000\).2. If squaring happens first, \(x\) becomes 100, then the cubing operation might read 100 and cube it, resulting in \(x = (100)^3 = 1000000\).3. If either operation solely completes without any interference from the other, \(x\) might be 100 or 1000, depending on whether squaring or cubing finishes first.
05

Understanding Serialized Execution

Serialized execution means the operations will run in a definite sequence. Here, a serializer `s` is used, ensuring that the two procedures execute one after the other, removing any non-determinism. The instructions call the squaring operation first, then the cubing operation.
06

Result of Serialized Execution

With serialization, the operations run in a strict sequence: 1. Squaring: \(x = 10^2 = 100\).2. Cubing: \(x = 100^3 = 1000000\).Thus, after serialized execution, \(x\) will consistently result in 1000000.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Serialization
Serialization is a mechanism to control the execution sequence of concurrent processes, ensuring they follow a specific order. Think of it as a method to line up tasks in a queue so that each task is executed one after the other, rather than at the same time.

This is essential when tasks can interfere with each other, such as updating the same variable in our example. By using serialization, like the 'make-serializer' in the exercise, we prevent the tasks of squaring and cubing the variable from running simultaneously, reducing unpredictability. It ensures the results are consistent and reliable, by forcing one task to complete before the next one begins. This method is crucial when you need to maintain a specific state or outcome.
  • Controls sequence execution
  • Prevents simultaneous task interference
  • Ensures consistent results
Non-Determinism
Non-determinism in programming refers to outcomes that can vary unpredictably due to operations executed concurrently, especially without explicit control.

In the given exercise, multiple outcomes for the variable 'x' arise because the squaring and cubing operations are executed in parallel. The end value may differ because the order in which each operation occurs can change from one execution to another. This unpredictable behavior is called non-determinism. It leads to situations where you cannot be certain of what the final result will be without additional control, such as serialization.
  • Unpredictable execution order
  • Different outcomes possible
  • Requires control for consistency
Operations Sequencing
Operations sequencing is the intentional arrangement in which tasks or instructions are executed to achieve a desired result.

In programming, the order of operations can significantly affect output, particularly when they modify a shared variable. In our exercise, this is evident when considering the sequence of squaring followed by cubing versus cubing followed by squaring. These different sequences can yield different results unless a mechanism like serialization is in place to enforce a specific order. Hence, understanding and controlling the sequence is vital to ensure a program behaves as intended.
  • Directs task order
  • Affects program outcome
  • Critical in concurrent settings
Mutable State
Mutable state refers to the ability of a variable or data structure to be modified after it is created. In programming, variables like 'x' in our exercise can have their value changed by different operations.

This mutability is both powerful and precarious. It allows for dynamic data changes but also risks unintended side effects if multiple operations change the state simultaneously. In concurrent programming, handling mutable states delicately is crucial since overlapping updates can lead to incorrect or unexpected program behavior. Serialization helps manage these mutable states by ensuring changes occur in a controlled sequence, thereby maintaining integrity and predictability.
  • Data can be changed
  • Allows flexibility but can introduce hazards
  • Requires careful handling in concurrent environments

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Memoization (also called tabulation) is a technique that enables a procedure to record, in a local table, values that have previously been computed. This technique can make a vast difference in the performance of a program. A memoized procedure maintains a table in which values of previous calls are stored using as keys the arguments that produced the values. When the memoized procedure is asked to compute a value, it first checks the table to see if the value is already there and, if so, just returns that value. Otherwise, it computes the new value in the ordinary way and stores this in the table. As an example of memoization, recall from section \(1.2 .2\) the exponential process for computing Fibonacci numbers: \(\begin{aligned}(\text { define }(f i b ~ n)& \\\\(\text { cond }((=\mathrm{n})&0) \\ &((=\mathrm{n} 1)&1) \\ &(e l s e(+(f i b(-\mathrm{n} 1))\\\ & &(f i b(-\mathrm{n}&2))))) \end{aligned}\) The memoized version of the same procedure is \(\begin{aligned}&\text { (define memo-fib } \\\&\text { (memoize (lambda ( } \mathrm{n} \text { ) } \\\&\begin{array}{rll}\text { (cond } & ((=\mathrm{n} & 0) & 0) \\ & ((=\mathrm{n} & 1) & 1)\end{array} \\\& & (\text { else (+ (memo-fib (-n 1)) } \\\& & \end{aligned}\) where the memoizer is defined as (define (memoize f) (let ((table (make-table))) (lambda (x) (let ((previously-computed-result (lookup x table))) (or previously-computed-result (let ((result (f x))) (insert! x result table) result)))))) Draw an environment diagram to analyze the computation of (memo-fib 3 ). Explain why memo-fib computes the \(n\)th Fibonacci number in a number of steps proportional to \(n\). Would the scheme still work if we had simply defined memo-fib to be (memoize fib)?

Louis Reasoner wants to build a squarer, a constraint device with two terminals such that the value of connector b on the second terminal will always be the square of the value a on the first terminal. He proposes the following simple device made from a multiplier: (define (squarer a b) (multiplier a a b)) There is a serious flaw in this idea. Explain.

Using primitive multiplier, adder, and constant constraints, define a procedure averager that takes three connectors \(\mathrm{a}, \mathrm{b}\), and \(\mathrm{c}\) as inputs and establishes the constraint that the value of \(c\) is the average of the values of a and \(b\).

Write a procedure triples that takes three infinite streams, \(S, T\), and \(U\), and produces the stream of triples \(\left(S_{i}, T_{j}, U_{k}\right)\) such that \(i \leq j \leq k\). Use triples to generate the stream of all Pythagorean triples of positive integers, i.e., the triples \((i, j, k)\) such that \(i \leq j\) and \(i^{2}+j^{2}=k^{2}\).

Instead of representing a queue as a pair of pointers, we can build a queue as a procedure with local state. The local state will consist of pointers to the beginning and the end of an ordinary list. Thus, the make-queue procedure will have the form (define (make-queue) (let ((front-ptr ...) (rear-ptr ...)) (definitions of internal procedures) (define (dispatch m) ...) dispatch)) Complete the definition of make-queue and provide implementations of the queue operations using this representation.

See all solutions

Recommended explanations on Computer Science Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free