Question

Write an if statement that displays "Digit" if the string referenced by the variable ch contains a numeric digit. Otherwise, it should display "No digit."

Short answer

Question: Given a string ch, write an if statement that checks if the string contains a numeric digit and displays "Digit" if true, and "No digit" if false. Answer: ```python ch = '5' if ch.isdigit(): print("Digit") else: print("No digit") ```

Step-by-step solution

Initialize the string variable ch

Assign a string value to the variable 'ch'. Make sure to assign a value to 'ch' before proceeding with the if statement to avoid any errors. For example, you can write `ch = '5'` in your code.

Check if the string contains a numeric digit

To determine if the string referenced by 'ch' contains a numeric digit, you can use the isdigit() method. This method returns True if the string contains a digit, and False otherwise. In the if statement, write the condition as `ch.isdigit()`.

Display "Digit" if the condition is met

If the condition in Step 2 is True (i.e., the string contains a numeric digit), then the program should display "Digit". To do this, add the following code within the if statement: `print("Digit")`.

Display "No digit" if the condition is not met

If the condition in Step 2 is False (i.e., the string does not contain a numeric digit), then the program should display "No digit". To do this, add the following code in an 'else' statement that follows the if statement: `print("No digit")`. The final if statement should look like this: ``` ch = '5' if ch.isdigit(): print("Digit") else: print("No digit") ```