Question

Write a statement that creates a two-dimensional list with three rows and four columns. Each element should be assigned the value 0 .

Short answer

Question: Create a two-dimensional list with three rows and four columns, and assign the value 0 to each element using nested loops. Answer: You can create a two-dimensional list with three rows and four columns and initialize each element to 0 using the following code: ```python matrix = [[0 for col_index in range(4)] for row_index in range(3)] ```

Step-by-step solution

Create an empty list for the two-dimensional list

First, create an empty list called 'matrix' that will hold the rows and columns of the two-dimensional list. ```python matrix = [] ```

Create rows using a for loop

Use a for loop to create the rows of the matrix. The loop should iterate three times, which is the number of rows in the matrix. ```python for row_index in range(3): row = [] matrix.append(row) ``` At this point, 'matrix' contains three empty rows.

Create columns and assign the value 0 to each element using a nested for loop

Inside the first for loop, add another for loop that iterates four times, which is the number of columns in the matrix. In this inner loop, append the value 0 to the 'row' list. ```python for row_index in range(3): row = [] for col_index in range(4): row.append(0) matrix.append(row) ``` Now, 'matrix' contains three rows, each with four columns, and all elements are assigned the value 0.

Final statement to create the two-dimensional list

Combine the loops in the previous steps to create the two-dimensional list with three rows and four columns, with all elements having the value 0. Here is the final statement: ```python matrix = [[0 for col_index in range(4)] for row_index in range(3)] ``` This statement combines the two loops to create the two-dimensional list called 'matrix', with each element being initialized to 0.