Question

After the following code executes, what elements will be members of set3? set1 = set(['a', 'b', 'c']) set2 = set(['b', 'c', 'd']) set3 = set1.symmetric_difference(set2)

Short answer

Answer: The symmetric difference between set1 and set2 is {'a', 'd'}.

Step-by-step solution

Define the sets

Assign the given sets to set1 and set2 variables: set1 = set(['a', 'b', 'c']) set2 = set(['b', 'c', 'd'])

Perform the symmetric difference operation

Now, perform the symmetric_difference operation on set1 and set2 to obtain set3: set3 = set1.symmetric_difference(set2)

List the elements in set3

After performing the symmetric_difference operation, list the elements that will be present in set3. According to the definition of symmetric difference, set3 will contain the elements that are in either set1 or set2 but not in both. Which are 'a' and 'd' in this case: set3 = {'a', 'd'} So, after the given code executes, set3 will contain the elements 'a' and 'd'.