Question

To pass an array to a function, pass the name of the array.

Short answer

Answer: To pass an array to a function in C++, you need to mention the data type, an empty set of square brackets, and the parameter name in the function definition, like this: `void processArray(int arr[], int size)`. Within the function, you can access the elements of the array using the parameter name and indices within square brackets, e.g., `arr[i]`. To call the function, provide the array's name followed by any additional necessary parameters, such as the array's size.

Step-by-step solution

Create a function that accepts an array as a parameter

To pass an array to a function in C++, you need to mention the data type, an empty set of square brackets, and the parameter name. You can also specify the array's size within the square brackets, but it's optional in this case. Here is a sample function that takes an integer array: ```c++ void processArray(int arr[], int size) { // Function implementation } ```

Access array elements within the function

Inside the function, you can access the elements of the array using the parameter name and indices within square brackets. For example, you could loop through the array and print the elements: ```c++ void processArray(int arr[], int size) { for(int i = 0; i < size; i++) { cout << "Element at index " << i << ": " << arr[i] << endl; } } ```

Pass the array to the function

To pass an array to the function, you just need to provide the array's name followed by necessary parameters. Let's assume you have the following array and its size: ```c++ int main() { int myArray[] = {1, 2, 3, 4, 5}; int arraySize = sizeof(myArray) / sizeof(myArray[0]); processArray(myArray, arraySize); return 0; } ``` In this example, `myArray` is passed to the `processArray` function for processing. The function then prints out the elements of the array as it processes them.