Question

True or False If the starting address of a C-string is passed into a pointer parameter, it can be assumed that all the characters, from that address up to the byte that holds the null terminator, are part of the string.

Short answer

Explain your answer. Answer: True. This is because a C-string is an array of characters terminated by a null character ('\0'). When passing the starting address of a C-string to a pointer parameter, the pointer points to the first character of the C-string. Thus, including the characters from the starting address up to the byte that holds the null terminator ensures that we consider the whole C-string.

Step-by-step solution

Understanding the nature of a C-string

A C-string is an array of characters that is terminated by a null character ('\0'). When you define a C-string, the size of the string is automatically adjusted to accommodate the null character.

Passing a C-string to a pointer parameter

When passing a C-string to a pointer parameter, we usually pass the starting address of the string. This means that the pointer parameter will now point to the first character of the C-string.

Analyzing the statement

Considering the nature of the C-string and how it's passed into a pointer parameter, starting from the address of the first character up to the byte that holds the null terminator, taking into account the fact that when a string is declared in C, it's an array of characters terminated by a null character ('\0'), it seems that the statement is correct as it ensures the whole C-string has been passed.

Conclusion

The statement given in the exercise is True. If the starting address of a C-string is passed into a pointer parameter, it can be assumed that all characters, from that address up to the byte that holds the null terminator, are part of the string since the C-string is represented as an array of characters terminated by a null character.