Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Write a definition statement for a character array named city. It should be large enough to hold a string 30 characters in length.

Short Answer

Expert verified
Question: Write a definition statement for a character array named 'city' capable of holding a string with a length of 30 characters. Answer: In C or C++, you would write `char city[31];` and in Java, you would write `char[] city = new char[31];` to define a character array named 'city' capable of holding a string of 30 characters.

Step by step solution

01

Choosing the Correct Data Type

To store an array of characters, we need to use the char data type. Char is used for storing single characters, but when combined into an array, it can hold strings.
02

Define the Size of the Array

We want our character array to be able to hold a string of 30 characters in length, so we need to set the size of the array accordingly. However, since in most programming languages strings end with a null terminator, we need to add an extra space for this, making the size of the array 31.
03

Write the Definition Statement

By combining the data type and the size of the array, we can now write the definition statement for the character array named 'city'. In C or C++: ```c char city[31]; ``` In Java (using an array of char): ```java char[] city = new char[31]; ```

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A retail store grants its customers a maximum amount of credit. Each customer's available credit is his or her maximum amount of credit minus the amount of credit used. Write a pseudocode algorithm for a program that asks for a customer's maximum amount of credit and amount of credit used. The program should then display the customer's available credit.

include #include using namespace std; int main() { const in SIZE = 20; char userInput[SIZE]; cout <… # (Assume the user enters George Washington.) #include #include using namespace std; int main() { const in SIZE = 20; char userInput[SIZE]; cout << "What is your name? "; cin >> setw(SIZE) >> userInput; cout << "Hello " << userInput << endl; return 0; }

define SIZE 12 How will the preprocessor rewrite the following lines? A) price = SIZE * unitCost; B) c… # Assume the following preprocessor directive appears in a program: #define SIZE 12 How will the preprocessor rewrite the following lines? A) price = SIZE * unitCost; B) cout << setw(SIZE) << 98.7; C) cout << SIZE;

include #include using namespace std; int main() { const in SIZE = 20; char userInput[SIZE]; cout <<… # (Assume the user enters George Washington.) #include #include using namespace std; int main() { const in SIZE = 20; char userInput[SIZE]; cout << "What is your name? "; cin.getline(userInput, SIZE); cout << "Hello " << userInput << endl; return 0; }

Assume a program has the following variable definitions: int units; float mass; double weight; and the following statement: weight = mass * units; Which automatic data type conversion will take place? A) mass is demoted to an int, units remains an int, and the result of mass * units is an int. B) units is promoted to a float, mass remains a float, and the result of mass * units is a float. C) units is promoted to a float, mass remains a float, and the result of mass * units is a double.

See all solutions

Recommended explanations on Computer Science Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free