Question

Write a cout statement so the variable divsales is displayed in a field of 8 spaces, in fixed point notation, with a precision of 2 decimal places. The decimal point should always be displayed.

Short answer

Answer: To display the value of "divsales" in the desired format, you can use the `fixed`, `setw`, and `setprecision` manipulators in the cout statement like this: ```cpp std::cout << std::fixed << std::setw(8) << std::setprecision(2) << divsales << std::endl; ``` Don't forget to include the `` and `` libraries at the beginning of your code.

Step-by-step solution

Include the necessary libraries

Before writing the code, we need to include the libraries that provide the manipulators for printing the output in the required format. Include the following libraries at the beginning of the code: ```cpp #include #include ```

Declare and initialize the divsales variable

Declare and initialize the `divsales` variable as a floating-point or double type. For example: ```cpp double divsales = 1234.56; ```

Apply the formatting options to the cout statement

In the cout statement, use the `fixed`, `setw`, and `setprecision` manipulators to set the fixed point notation, the field width, and the precision, respectively. The statement should look like this: ```cpp std::cout << std::fixed << std::setw(8) << std::setprecision(2) << divsales << std::endl; ``` Here's how the complete code should look: ```cpp #include #include int main() { double divsales = 1234.56; std::cout << std::fixed << std::setw(8) << std::setprecision(2) << divsales << std::endl; return 0; } ``` When the code is executed, it will display the value of `divsales` in a field of 8 spaces, with 2 decimal places and a fixed decimal point.