Question

Look at the following array definition. char str [10] Assume that name is also a char array, and it holds a C-string. Write code that copies the contents of name to str if the C-string in name is not too big to fit in str.

Short answer

Question: Write a code that checks and copies the contents of the array `name` into `str` if the C-string `name` is not too big to fit into `str`. Answer: To copy the contents of `name` into `str`, you can use the following code: ```c #include #include int main() { char str[10]; char name[] = "John"; if (strlen(name) < sizeof(str)) { strcpy(str, name); } return 0; } ```

Step-by-step solution

Include necessary header files

In order to use the functions `strlen()` and `strcpy()`, we need to include the necessary header files in our code. In this case, we need to include the `` header file for `strlen()` and `strcpy()` functions. ```c #include #include ```

Declare the char arrays

Now, we need to declare the `char` arrays `str` and `name`. In this example, we assume that `name` is already declared and initialized with a value as a C-string. We declare `str` as an array of size 10. ```c char str[10]; char name[] = "John"; ```

Check the length of the 'name'

We need to check if the length of the C-string `name` is less than the size of the `str` array. This can be done using the `strlen()` function. It returns the length of the C-string without counting the null character. ```c if (strlen(name) < sizeof(str)) { // Copy the contents of the 'name' to 'str' } ```

Copy contents of 'name' to 'str'

If the length of the C-string `name` is less than the size of the `str` array, we can copy the contents from `name` to `str` using the `strcpy()` function. ```c if (strlen(name) < sizeof(str)) { strcpy(str, name); } ```

Complete code

Here is the complete code to perform the operation: ```c #include #include int main() { char str[10]; char name[] = "John"; if (strlen(name) < sizeof(str)) { strcpy(str, name); } return 0; } ```