Question

Look at the following array definition. double sales [8][10] A) How many rows does the array have? B) How many columns does the array have? C) How many elements does the array have? D) Write a statement that stores 3.52 in the last column of the last row in the array.

Short answer

Answer: The array "sales" has 8 rows and 10 columns. The total number of elements in the array is 80. To store a value (e.g. 3.52) in the last column of the last row, use the statement: sales[7][9] = 3.52;

Step-by-step solution

Answer A - Calculating the number of rows

To find the number of rows in the array, look at the first dimension of the array definition, which is 8. That means the array has 8 rows.

Answer B - Calculating the number of columns

To find the number of columns in the array, look at the second dimension of the array definition, which is 10. That means the array has 10 columns.

Answer C - Calculating the number of elements

The total number of elements in a 2D array can be found by multiplying the number of rows by the number of columns. In this case, we have 8 rows and 10 columns, so the total number of elements in the array is 8 * 10 = 80.

Answer D - Storing given value in the last column of the last row

To store the value 3.52 in the last column of the last row, we need to determine the index of the last row and the last column. Since arrays are zero-indexed (start counting from 0), the index of the last row would be 7 (one less than the number of rows), and the index of the last column would be 9 (one less than the number of columns). The statement to store the value 3.52 in the last column of the last row is: sales[7][9] = 3.52;