Question

Rewrite the following code, converting the while loop to a do-while loop: char doAgain \(=' y^{\prime}\) \\[ \text { int } \operatorname{sum}=0 \\] cout \( < < \) "This code will increment sum 1 or more times. \(| n "\) while ( (doAgain = = ' y') | | (doAgain = = 'Y') ) \(\\{\quad s u m++;\) cout \( < < \) "Sum has been incremented. Increment it again(y/n)? "; cin \(>>\) doAgain; \\} cout \( < < \) "Sum was incremented " \( < < \) sum \( < < "\) times. \(\backslash n "\)

Short answer

"; cin >> doAgain; } ``` Answer: ``` char doAgain; int sum = 0; do { sum++; cout << "Sum has been incremented. Increment it again(y/n)? "; cin >> doAgain; } while ((doAgain == 'y') || (doAgain == 'Y')); ```

Step-by-step solution

Understand the Structure of a Do-While Loop

A do-while loop has the following structure: ``` do { // Code to be executed } while (condition); ``` Where the "condition" determines whether the loop should be executed again.

Convert the While Loop to a Do-While Loop

To do that, we first need to place the code block inside a do-while loop. In our case, this block was originally inside the while loop: ``` sum++; cout << "Sum has been incremented. Increment it again(y/n)? "; cin >> doAgain; ``` Now, let's create a do-while loop with the original condition of the while loop and rerun the code: ``` char doAgain = 'y'; int sum = 0; do { sum++; cout << "Sum has been incremented. Increment it again(y/n)? "; cin >> doAgain; } while ((doAgain == 'y') || (doAgain == 'Y')); ``` Finally, we can now output the final value of the sum variable: ``` cout << "Sum was incremented " << sum << " times.\n"; ```