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Write a loop that asks the user to enter a number. The loop should iterate 10 times and keep a running total of the numbers entered.

Short Answer

Expert verified
Answer: The final result, the running total, should be displayed using the `print()` function after the loop is done.

Step by step solution

01

Initialize variables

First, initialize two variables: one to store the running total and another to count the number of iterations. Set both variables to 0.
02

Create a loop

Create a loop that will iterate 10 times. A `for` loop can be used here, with a range function to specify the number of iterations.
03

Ask the user for input

Inside the loop, use the `input()` function to get a number from the user. Make sure to convert the input to an integer using the `int()` function, as the `input()` function returns a string.
04

Update the running total

Add the user input to the running total variable.
05

Display the final result

After the loop is done, display the final running total using the `print()` function. Here's the code to complete the exercise: ```python # Step 1: Initialize variables running_total = 0 # Step 2: Create a loop for i in range(10): # Step 3: Ask the user for input user_input = int(input("Enter a number: ")) # Step 4: Update the running total running_total += user_input # Step 5: Display the final result print("The running total is:", running_total) ```

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Most popular questions from this chapter

Write a do-while loop that asks the user to enter two numbers. The numbers should be added and the sum displayed. The user should be asked if he or she wishes to perform the operation again. If so, the loop should repeat; otherwise it should terminate.

A loop that does not have a way of stopping is a(n) __________ loop.

include \(<\) iostream \(>\) using namespace std; int main() \\{ int choice, num1, num2; do \\{ cout \(<<\) "Enter a numbe… # A) / / This program displays the sum of two numbers. # include \(<\) iostream \(>\) using namespace std; int main() \\{ int choice, num1, num2; do \\{ cout \(<<\) "Enter a number: "; \\[ \operatorname{cin} \quad>>\text { num1 } \\] cout \(<<\) "Enter another number: " \\[ \operatorname{cin} \quad>>\text { num2 } \\] cout \(<<\) "Their sum is " \(<<(\text { num1 }+\text { num2 ) }<<\) endl; cout \(<<\) "Do you want to do this again? \\[ \begin{array}{l} \text { cout }<<" 1=\text { yes, } 0=\text { noln" } \\ \text { cin }>>\text { choice } \end{array} \\] }while (choice = 1) return 0 \\} B) // This program displays the sum of the numbers \(1-100\) # include using namespace std; int main () \\{ int count \(=1,\) total; while (count \(<=100\) ) total \(+=\) count cout \(<<\) "The sum of the numbers \(1-100\) is " cout \(<<\) total \(<<\) endl return 0 \\}

include \(<\) iostream \(>\) using namespace std; int main ( ) \(\\{\) int num, bigNum, power, count; cout \(<<\) "… # A) // This program uses a loop to raise a number to a power. # include \(<\) iostream \(>\) using namespace std; int main ( ) \(\\{\) int num, bigNum, power, count; cout \(<<\) "Enter an integer: "; \(\operatorname{cin} \quad>>\) num cout \(<<\) "What power do you want it raised to? "; cin \(>>\) power bigNum \(=\) num; while (count++ \(<\) power); bigNum \(*=\) num; cout \(<<\) "The result is \(<<\) bigNum \(<<\) endl return 0 \\} B) // This program averages a set of numbers. # include using namespace std; int main() \\{ int numcount, total; double average; cout \(<<\) "How many numbers do you want to average? "; cin \(>>\) numcount for \((\text { int count }=0 ; \text { count }<\text { numcount } ; \text { count }++)\) \\{ int num; cout \(<<\) "Enter a number: "; \\[ \operatorname{cin} \quad>>\text { num } \\] total \(+=n u m\) count \(++\) \\} average \(=\) total / numCount; cout \(<<\) "The average is \(<<\) average \(<<\) endl return 0 \\}

To __________ a value means to increase it by one.

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