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The __________ points to the first node in a linked list.

Short Answer

Expert verified
Answer: Head

Step by step solution

01

Identifying the linked list term

In a linked list, nodes store elements of the data structure and have a reference or link to the next node in the sequence. The term we are looking for points to the first node in the linked list.
02

Answer

The term that points to the first node in a linked list is called the "Head".

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Most popular questions from this chapter

Each of the following member functions for performing an operation on a linked list of type NumberList has at least one error. Explain what is wrong and how to fix it. A) NumberList: :printList ( ) while (head) cout \(<<\) head- \(>\) value head \(=\) head- \(>\) next B) NumberList: :printList ( ) ListNode \(\star \mathrm{p}=\) head; while \((\mathrm{p}->\text { next })\) cout \(<\) value \(p=p->n e x t\) C) NumberList: :printList ( ) Listrode \(* p=\) head while \((p)\) cout \(<\) value \(p++;\) D) NumberList: : NumberList ( ) ListNode \(*\) nodePtr, *nextNode; nodePtr = head; while (nodePtr != NULL) nextNode \(=\) nodePtr-next nodePtr- \(>\) next \(=\) NULL \(;\) nodePtr \(=\) nextNode;

To indicate that a linked list is empty, you should set the pointer to its head to the value __________.

Using the ListNode structure introduced in this chapter, write a function void printFirst(ListNode *ptr) that prints the value stored in the first node of a list passed to it as parameter. The function should print an error message and terminate the program if the list passed to it is empty.

Write a function ListNode *ListConcat(ListNode *list1, ListNode *list2) That concatenates the items in list2 to the end of list1 and returns the resulting list.

Write a function void printSecond(ListNode *ptr) that prints the value stored in the second node of a list passed to it as parameter. The function should print an error message and terminate the program if the list passed to it has less than two nodes.

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