Question

Each of the following functions contains errors, Locate as many as you can. A) void showValues (Int nums) for (Int count = 0; count < 8; count++) cout \(\langle\langle\text { nums }[\text { count }]\) B) void showValues (int nums \([4][])\) for \((\text { rovs }=0: \text { rows }\langle 4: \text { rows++})\) For \((\operatorname{cols}=0: \operatorname{cols}<5: \operatorname{cols}++)\) cout \(<<\) nums [rows] [cols] :

Short answer

Question: Identify and correct the errors in the given functions A and B. Function A: ``` void showValues (Int nums) for (Int count = 0; count < 8; count++) cout << nums[count] ``` Function B: ``` void showValues (int nums[4][]) for (rows=0: rows<4: rows++) For(cols=0: cols<5: cols++) cout << nums[rows][cols] ```

Step-by-step solution

Locate Errors in Function A

The given function A is: ``` void showValues (Int nums) for (Int count = 0; count < 8; count++) cout << nums[count] ``` The errors in function A are: 1. The function parameter should have a lowercase 'i' for int, not an uppercase 'I'. 2. The function parameter should be an array, so it should be followed by square brackets []. 3. The function body should be enclosed within curly braces {}. After correcting the errors, the corrected function A is: ``` void showValues (int nums[]) { for (int count = 0; count < 8; count++) { cout << nums[count]; } } ```

Locate Errors in Function B

The given function B is: ``` void showValues (int nums[4][]) for (rows=0: rows<4: rows++) For(cols=0: cols<5: cols++) cout << nums[rows][cols] ``` The errors in function B are: 1. The function parameter should specify the second dimension of the array. It should be followed by square brackets [][5]. 2. The loop variables 'rows' and 'cols' should be declared as int and properly initialized with for loop syntax using the semicolon (;) separator. 3. The nested for loops should use lowercase 'for' and must be enclosed within curly braces {}. After correcting the errors, the corrected function B is: ``` void showValues (int nums[][5]) { for (int rows=0; rows<4; rows++) { for (int cols=0; cols<5; cols++) { cout << nums[rows][cols]; } } } ```