Question

Use the following Car structure declaration to answer questions \(28-30\). struct Car string make model: Int year: double cost: // Constructors \(\operatorname{Car}()\) { make \(=\) model \(=" " ;\) year \(=\cos t=0: 1\) } Car(string mk, string md. int yr, double c) { make \(=\) whe model \(=\) ind : year \(=y r ; \quad \cos t=c: 1\)} Define an array named for Sale that holds 35 Car structures. Initialize the first three elements with the following data: $$\begin{array}{llll} \text { Make } & \text { Model } & \text { Year } & \text { cost } \\ \text { Ford } & \text { Taurus } & 2002 & \$ 21,000 \\ \text { Honda } & \text { Accord } & 2001 & \$ 11,000 \\ \text { Jeep } & \text { Wrangler } & 2004 & \$ 24,00000 \end{array}$$

Short answer

Answer: To create an array with 35 Car structures, declare it as "Car forSale[35];". Then, initialize the first three elements using their respective constructors: 1. forSale[0] = Car("Ford", "Taurus", 2002, 21000); 2. forSale[1] = Car("Honda", "Accord", 2001, 11000); 3. forSale[2] = Car("Jeep", "Wrangler", 2004, 24000);

Step-by-step solution

Create an array of Car structures

To create an array that holds 35 Car structures, use "Car forSale[35];".

Initialize the first element

Use the constructor with all parameters provided to initialize the first element of the array: "forSale[0] = Car("Ford", "Taurus", 2002, 21000);".

Initialize the second element

Use the constructor with all parameters provided to initialize the second element of the array: "forSale[1] = Car("Honda", "Accord", 2001, 11000);".

Initialize the third element

Use the constructor with all parameters provided to initialize the third element of the array: "forSale[2] = Car("Jeep", "Wrangler", 2004, 24000);".