Question

Given the following array definition: \\[\text { Int values }[5]=(4,7,6,8,2)\\] What does the following statement display? $$\begin{array}{l} \text { cout }\langle\langle\text { values }[4] \ll x \quad \text { " }\langle\langle\quad \text { (values }[2]+\text { values }[3]) \\ \quad\langle\langle\quad \text { " } \quad \text { " } \quad\langle\langle\text { ++values }[1] \quad\langle\langle\text { end } 1 \end{array}$$

Short answer

Answer: The output displayed will be "2 x 14 8".

Step-by-step solution

Understand the array

The array 'values' is defined as having 5 elements: (4, 7, 6, 8, 2). The indexing starts from 0, so 'values[0]' refers to the first element (4), 'values[1]' refers to the second element (7), and so on.

Identify the output of values[4]

Here, the statement displays the value at the fourth index of the array, which is 2. Remember that the indexing starts from 0. So, 'values[4]' refers to the last element of the array.

Analyze the part "" (values[2] + values[3])

In this part of the statement, it calculates the sum of the values in the second and third indexes, which are 6 and 8 (values[2] = 6 and values[3] = 8). So, the sum is 6 + 8 = 14.

Analyze the part "++values[1]"

The '++' operator is a pre-increment operator, which means it increments the value of the variable before it's used in the expression. In this case, it increments the value at index 1 (which is 7) by 1, resulting in the new value of 8.

Combine the outputs to form the final output

We have obtained the following values from the statement: 1. values[4] = 2 2. (values[2] + values[3]) = 14 3. ++values[1] = 8 The final output of the statement will be: "2 x 14 8". So, the output displayed by the given statement will be "2 x 14 8".