Question

What will each of the following program segments display? $$\begin{array}{c} \operatorname{int} \mathrm{x}=1 ; \\ \text { while }(\mathrm{x} < 10) \\ \mathrm{x}++ \\ \text { cout } < < \mathrm{x}; \end{array}$$

Short answer

Answer: The output of the code will be 2 3 4 5 6 7 8 9.

Step-by-step solution

Initialize variable x

Declare and initialize an integer variable x with the value 1. So, x = 1.

Evaluate the while loop with given condition

We have the condition: \(x < 10\). Initially, x = 1, so the loop condition is true, and we will enter the while loop.

Increment x value inside the loop

Inside the loop, increment the value of x by 1 using the 'x++' operation. So, x will be increased to 2.

Output the new value of x

After incrementing x's value, the code will execute the 'cout << x;' statement, which will output the current value of x. At this point in the code, x = 2, so it will print "2".

Continue to iterate through the while loop

The loop condition is still true (2 < 10), so the while loop will continue to repeat steps 3 and 4 until the loop condition becomes false. Following the same process, the output will be: 2 3 4 5 6 7 8 9

Exit the while loop when the condition becomes false

When x = 10, the loop condition will become false since 10 is not less than 10. At this point, the while loop will end, and the code execution will be complete. The output of this program will be: 2 3 4 5 6 7 8 9