Question

A variable with __________ scope is only visible when the program is executing in the block containing the variable’s definition.

Short answer

Answer: The type of variable scope described is local or block scope. An example of this would be: ```cpp #include using namespace std; int main() { { int localVar = 10; // localVar is visible only within this block cout << "Local variable value: " << localVar << endl; } // localVar is not accessible here, it's out of scope return 0; } ``` In this C++ code example, the variable `localVar` is declared within a block and is only visible within that block. It is not accessible outside of the block.

Step-by-step solution

Understand variable scope

Variable scope refers to the part of the code where a particular variable is accessible and visible. There are different types of scopes, such as global scope, local scope, and block scope.

Identify the variable scope described in the exercise

The exercise describes a variable scope where the variable is only visible within the block containing its definition. This type of variable scope is known as the local scope or block scope.

Explain local or block scope

In programming, a block is a section of code enclosed within braces { }. Local or block scope means that the variable is accessible only within the specific block it is defined in. Once the block of code containing the variable is done executing, the variable is no longer accessible.

Provide an example of local or block scope

Consider the following C++ code example demonstrating the use of a local variable: ```cpp #include using namespace std; int main() { { int localVar = 10; // localVar is visible only within this block cout << "Local variable value: " << localVar << endl; } // localVar is not accessible here, it's out of scope return 0; } ``` In this example, the variable `localVar` is declared within a block and is only visible within that block. It is not accessible outside of the block, so if you tried to access it or manipulate it outside of the block, you would get a compilation error.