Question

Rewrite the follow statement to use the newline escape character, instead of an end1, each time subsequent output is to be displayed on a new line. \\[ \begin{aligned} \text { cout } &<<\quad \text { "L" }<<\text { end } 1 \\ &<<\text { "E" }<<\text { end } 1 \\ &<<\text { "A" }<<\text { end } 1 \\ &<<\text { "F" }<<\text { end } \end{aligned} \\]

Short answer

Question: Rewrite the given C++ code snippet using the newline escape character \n instead of std::endl to display the characters "L", "E", "A", and "F" on separate lines. Solution: ``` cout << "L" << "\n" << "E" << "\n" << "A" << "\n" << "F" << "\n"; ```

Step-by-step solution

Identify the output statement

The text characters are displayed using the "cout" statement. We are given the following code snippet that uses "endl" to move to a new line after each character: ``` cout << "L" << endl; cout << "E" << endl; cout << "A" << endl; cout << "F" << endl; ```

Replace 'endl' with newline escape character '\n'

In the provided code snippet, we replace each instance of "endl" with the newline escape character "\n": ``` cout << "L" << "\n"; cout << "E" << "\n"; cout << "A" << "\n"; cout << "F" << "\n"; ```

Combine "cout" statements

Finally, we can combine the separate "cout" statements into one statement using "<<": ``` cout << "L" << "\n" << "E" << "\n" << "A" << "\n" << "F" << "\n"; ``` The rewritten C++ code snippet that uses a newline escape character instead of "endl" to display the characters on separate lines is: ``` cout << "L" << "\n" << "E" << "\n" << "A" << "\n" << "F" << "\n"; ```