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Consider the following code (and assume that it is embedded in a complete and correct program and then run): string s; cout << "Enter a line of input:\n"; getline(cin, s); cout << s << "

Short Answer

Expert verified
Answer: A string is a joy forever!<END OF OUTPUT

Step by step solution

01

Analyze the code

We must understand what the given code does. The code is asking the user to enter a line of input, and then it reads that input using getline function, which stores that input in the string variable 's'. After that, it prints the content of the string 's' followed by the tag "<END OF OUTPUT".
02

Identify the input

The input is provided as the line "A string is a joy forever!".
03

Use the input in the code to determine the output

Now, we know the input, and we know what the code does with the input. When we input "A string is a joy forever!", that value will be stored in the string variable 's'. Then, the program prints the content of 's' along with the tag "<END OF OUTPUT". Therefore, the next line of output will be "A string is a joy forever!<END OF OUTPUT".

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