Question

What string will be output when this code is run? (Assume, as always, that this code is embedded in a complete, correct program.) char song[10] = "I did it "; char franks_song[20]; strcpy ( franks_song, song ); strcat ( franks_song, "my way!"); cout << franks_song << endl;

Short answer

Answer: The output of the code is "I did it my way!".

Step-by-step solution

Initialize character arrays

In this step, two character arrays are initialized: 1. song array: `char song[10] = "I did it ";` 2. franks_song array: `char franks_song[20];` The array 'song' has a size of 10 and is initialized with the string "I did it ". The array 'franks_song' has a size of 20 and is not initialized yet.

Copy the content of 'song' into 'franks_song'

In this step, the content of 'song' is copied into 'franks_song' using the strcpy function: `strcpy ( franks_song, song );`. After this line is executed, the content of 'franks_song' becomes "I did it ".

Concatenate 'franks_song' with "my way!"

In this step, the string "my way!" is concatenated to 'franks_song' using the strcat function: `strcat ( franks_song, "my way!" );`. After this line is executed, the content of 'franks_song' becomes "I did it my way!".

Print the final output

Finally, the content of 'franks_song' is printed using the 'cout' statement: `cout << franks_song << endl;`. As we know, 'franks_song' now contains the string "I did it my way!", so this is the output when the code is run.