Question

include void friendly( ); void shy(int audience_count); int main( ) { using namespace std; friendly( ); shy(6); … # What is the output of the following program? #include void friendly( ); void shy(int audience_count); int main( ) { using namespace std; friendly( ); shy(6); cout << "One more time:\n"; shy(2); friendly( ); cout << "End of program.\n"; return 0; } void friendly( ) { using namespace std; cout << "Hello\n"; } void shy(int audience_count) { using namespace std; if (audience_count < 5) return; cout << "Goodbye\n"; } The \(\mathrm{C}++\) Standard says that you can omit the return \(\theta\) in the main part, but many compilers still require it.

Short answer

Answer: The final output of the given C++ program is: ``` Hello Goodbye One more time: Hello End of program. ```

Step-by-step solution

Function `friendly`

The function `friendly` simply displays "Hello" in the console using the `cout` statement.

Function `shy(int audience_count)`

The function `shy` takes an integer parameter `audience_count` and checks if the value is less than 5. If it is less than 5, the function returns without any action. If the value is equal to or greater than 5, it displays "Goodbye" in the console.

Analyzing the sequence of function calls in `main`

The main function includes the following sequence of function calls and statements: 1. Call `friendly()`: It will display "Hello". 2. Call `shy(6)`: Parameter is greater than or equal to 5, so it will display "Goodbye". 3. Print "One more time:\n": This will display "One more time:" and a newline. 4. Call `shy(2)`: Parameter is less than 5, so no output. 5. Call `friendly()`: It will display "Hello". 6. Print "End of program.\n": The statement displays "End of program." and a newline.

Writing out the final output

Based on the above analysis, the output of the given program will be as follows: ``` Hello Goodbye One more time: Hello End of program. ```